Answer:
The answer is 17/80.
Step-by-step explanation:
Answer: Here is your answer. Mark as brainlist please :)
The required solution is ∠RQT = 202° and ∠QTS = 51°
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<h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.
Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.
Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°
Since,sum of the opposite angles of a cyclic quadrilateral = 180°
⇒∠QTS + ∠QRS = 180°
⇒ ∠QTS + ∠129° = 180°
⇒ ∠QTS = 180° - ∠129°
⇒ ∠QTS = 51°
Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.
More about cyclic quadrilateral :
brainly.com/question/14323008
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The answer for this would be NO. You can no longer reduce 9/10 since there is no factor that is similar between the two numbers. There is no other number that can also divide these numbers evenly except for 1. Therefore,it is already fixed and in the simplest form. Hope this answer helps.
