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3 years ago

Answer now please ‍♀️

Mathematics

1 answer:

Shtirlitz [24]3 years ago

3 0

Answer:

8/15

Step-by-step explanation:

In a right triangle, where B is an acute angle, the tan B is equal to the measure of the side opposite B divided by the measure of the shorter side at B

tanB = 16/30 = 8/15

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For a project, Gabrielle made a model of an Egyptian pyramid. The square base has a side length measuring 10 inches. The pyramid

Varvara68 [4.7K]

The pyramid is shown in the diagram below.
The pyramid is built from four congruent triangles and one square as the base

We have the side of the square, so the area is = 10×10 = 100

We need the height of the triangle to work out its area. We can find out by using the height of the pyramid and half of the length of the side of the square.

Using the Pythagoras rule
Height of triangle = $\sqrt{12^{2}+ 5^{2} } =13$

Area of one triangle = 1/2×10×12=60
Surface area of the pyramid = 100 + (4×60) = 340 square inches

3 0

3 years ago

Read 2 more answers

Round 4.16 to the nearest whole number?

frutty [35]

4.16 rounded to the nearest whole is 4.2.

3 0

3 years ago

Select all values of x that make the inequality true -x+6> 10 true .

Rufina [12.5K]

Answer:

C. -4.01

H. -7

Step-by-step explanation:

Solving inequalities:

We have a set of numbers to verify which ones of them make the below inequality true

$-x+6>10$

Rearrange

$-10+6>x$

Operating

$-4>x$

Flipping

$x$

The set of solutions contains every number less than -4

There are only two numbers less than -4 in the set of options:

C. -4.01

H. -7

4 0

3 years ago

Read 2 more answers

Graph the line with slope -1/3 passing through the point (2, 1).

bogdanovich [222]

Answer:

Step-by-step explanation:

y = mx + b

y = -x/3 + b

1 = -2/3 + b

b = 5/3

y = -x/3 + 5/3

5 0

2 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

Viefleur [7K]

Answer:

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then

$n = 1537, \pi = \frac{353}{1537} = 0.2297$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 - 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2087$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2297 + 1.96\sqrt{\frac{0.2297*0.7703}{1537}} = 0.2507$

The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).

7 0

3 years ago