Answer:
Δ SHD ≅ Δ STD (By SAS)
Step-by-step explanation:
Given:
SD⊥HT
SH=ST
Prove:
Δ SHD ≅ Δ STD
Computation:
SH=ST (Given)
SD = SD (Common)
∠SHD = ∠SDT (right angle) (SD⊥HT)
So,
Δ SHD ≅ Δ STD (By SAS)
4.16161616=41010101/6250000
Showing the work
Rewrite the decimal number as a fraction with 1 in the denominator
4.16161616=4.16161616/1
Multiply to remove 8 decimal places. Here, you multiply top and bottom by 10^8 = 100000000
4.16161616/1×100000000/100000000=416161616/100000000
Find the Greatest Common Factor (GCF) of 416161616 and 100000000, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 16,
416161616÷16/100000000÷16=26010101/6250000
Simplify the improper fraction,
=4 1010101/6250000
In conclusion,
4.16161616=4 1010101/6250000
Answer:
Step-by-step explanation:
No. If you reverse the prime number 23, you get 32 and that number is not a prime number.
Answer:
Last one
Step-by-step explanation:
You can simplify the first one or compare both of them if they have the same ratios! Hope this helps <3
Not sure if you can do this but it sounds like a velocity/time/distance equation.
d=vt
v=d/t
t=d/v
70 w/m = t
15 pages - 350 w/p
She can type 70 words per minute (w/m). There are 350 words per page (w/p). She needs 15 pages. So first you have to find how many words she can type in one hour. 60 minutes in an hour, she can type 70 w/p.
60x70=4,200 words per hour (w/h).
Next you should find out how many words on 15 pages total.
350x15= 5,250.
I would put 4,200/5,250 as a fraction to gage how much she has left. She has most of it done already in ONE HOUR. Reduced, she has done 4/5s of the essay. Now you just need to get 1/5 of 5250, which is 1050.
She needs to do 1050 words. If one minute is 70, do 1050/70 which is 15.
The answer is 1 hour and 15 minutes.
I think... ;)
