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Ronch [10]
3 years ago
11

What is the solution to the system of equations? y=1 y=-5x+3

Mathematics
2 answers:
In-s [12.5K]3 years ago
7 0

Answer:

y=1

x=2/5

Step-by-step explanation:

1=-5x+3

-2=-5x

x=2/5

AURORKA [14]3 years ago
7 0

Answer:

x = 2/5

Step-by-step explanation:

-5*2/5+3=1

x is 2/5

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nordsb [41]
LEAST COMMON MULTIPLE is 56

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3 years ago
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Gwar [14]

Answer:

If there is no 48 divided by 8 then it is 8 x _ = 48.

Step-by-step explanation:

Think about it. There are 6 times more children than adults *6 x 8 = 48.

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3 years ago
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How much larger is 6 times 10 to the 5th power compared to 2 times 10 to the 3rd power
lora16 [44]

Answer:

Either <em><u>10 times</u></em> or <u><em>598,000.</em></u>

Step-by-step explanation:

6 x 10 ^ 5 = 600,000

2 x 10 ^ 3 = 2,000

If we are figuring out the exact number, 600,000 - 2,000.  If we are finding out how many powers larger, count.

600,000 - 2,000 = 598,000

600,000 is 10 times larger than 2,000.

See?

600,0<u>00</u>

2,000

6 0
3 years ago
Nzwxecrtvbyvtrcexwzqzwxecrtvbynu 7 1/2÷56 nkjnknlnlk
Elden [556K]

Answer:

0.1

Step-by-step explanation:

0.13392857142857142857142857142857

8 0
2 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
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