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Scrat [10]
3 years ago
15

How much interest is earned in 2 years

Mathematics
1 answer:
WITCHER [35]3 years ago
5 0
600 it’s a estimation
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Find the value of x. Round to the nearest tenth. The diagram is not drawn to scale.
likoan [24]

Answer:

Cosine 24 = adjacent / hypotenuse (x)

0.91355  = 11 / hypotenuse

hypotenuse = 11 /  0.91355

hypotenuse (x) = 12.0409391933

or x = 12.04 (rounded)

Step-by-step explanation:

4 0
3 years ago
If an exterior angle of a regular polygon is 21.2º, how many sides does the polygon have?
brilliants [131]

Answer:

option 4.    17

Step-by-step explanation:

<u>sum of angles = exterior angle x n</u>

360° = 21.2° n

n = 360 / 21.2

n = 17

6 0
3 years ago
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Got another hard question. ​
Kamila [148]

Answer:

D) 1/2

Step-by-step explanation:

<u>Dilation</u> : a type of transformation that makes the figure larger or smaller.

<u>Scale factor</u> : number or the conversion factor which is used to change the size of a figure without changing its shape.

Scale factor = dimensions of the new shape ÷ dimensions of the original shape

Given:

  • Length of new figure P'Q' = 3 units
  • Length of original figure PQ = 6 units

Therefore, scale factor = 3 ÷ 6 = 1/2

7 0
2 years ago
Read 2 more answers
Verify the identity. cotangent of x divided by quantity one plus cosecant of x equals quantity cosecant of x minus one divided b
Elenna [48]

Answer:

\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}

Step-by-step explanation:

We want to verify the identity:

\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}

Let us take the LHS and simplify to get the LHS.

Express everything in terms of the cosine and sine function.

\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{1+\frac{1}{\sin x} }

Collect LCM

\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{\frac{\sin x+1}{\sin x} }

We simplify the RHS to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x}{\sin x+1}

We rationalize to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{(\sin x+1)*(\sin x-1)}

We expand to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{\sin^2 x-1}

Factor negative one in the denominator:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-(1-\sin^2 x)}

Apply the Pythagoras Property to get:

\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-\cos^2 x}

Simplify to get:

\frac{\cot x}{1+\csc x}=\frac{-(\sin x-1)}{\cos x}

Or

\frac{\cot x}{1+\csc x}=\frac{1-\sin x}{\cos x}

Divide both the numerator and denominator by sin x

\frac{\cot x}{1+\csc x}=\frac{\frac{1}{\sin x}-\frac{\sin x}{\sin x}}{\frac{\cos x}{\sin x}}

This finally gives:

\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}

8 0
2 years ago
Line A Is Parallel To Line B. If The Measure Of Z7 Is 114”, What Is The Measure Of 3​
Mkey [24]
Also 114 as they are corresponding angles
6 0
3 years ago
Read 2 more answers
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