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Answer:
Step-by-step explanation:
6
Answer:
The value of the test statistic is -3.14.
Step-by-step explanation:
Test statistic:
In which X is the sample mean, 
is the expected value, 
is the standard deviation and n is the size of the sample.
A company advertises that its cans of caviar each contain 100 g of their product.
This means that 
They calculate a sample mean weight of 99 g and a sample standard deviation of 0.9 g. Sample of 8 cans.
This means that 
So the test statistic will be given by:
The value of the test statistic is -3.14.
The difference in distance between Aero plane A and B is; 34.67 km
<h3>How to calculate bearing?</h3>
To get the bearing;
∠H = (115 - 90) + (270 - 203)
∠H = 92°
Then, we will use cosine rule to get the distance between both Planes A and B.
d_ab = √(18² + 29² - 2(18 * 29) * cos 92)
d_ab = √(324 + 841 + 36.435)
d_ab = 34.67 km
Read more about bearing at; brainly.com/question/22518031
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Answer:
a. The percentage of vehicles who pass through this construction zone who are exceeding the posted speed limit =90.82%
b. Percentage of vehicles travel through this construction zone with speeds between 50 mph and 55 mph= 2.28%
Step-by-step explanation:
We have to find
a) P(X>40)= 1- P(x=40)
Using the z statistic
Here
x= 40 mph
u= 44mph
σ= 3 mph
z=(40-44)/3=-1.33
From the z-table -1.67 = 0.9082
a) P(X>40)=
Probability exceeding the speed limit = 0.9082 = 90.82%
b) P(50<X<55)
Now
z1 = (50-44)/3 = 2
z2 = (55-44)/3= 3.67
Area for z>3.59 is almost equal to 1
From the z- table we get
P(55 < X < 60) = P((50-44)/3 < z < (55-44)/3)
= P(2 < z < 3.67)
= P(z<3.67) - P(z<2)
= 1 - 0.9772
= 0.0228
or 2.28%
