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ankoles [38]
3 years ago
12

Find the length of the hypotenuse of a right triangle and both legs have a length of 6

Mathematics
2 answers:
trasher [3.6K]3 years ago
7 0

Answer:

6\sqrt{2}

Step-by-step explanation:

a^2+b^2=c^2

6^2+6^2=c^2

36+36=c^2

72=c^2

square root 72 is the hypotenuse

Or simplified 6\sqrt{2}

Or decimal form 8.48528137424

Rounded 8.49

evablogger [386]3 years ago
3 0
A = short leg
B= short leg
C= hypotenuse

A^2+B^2=C^2
So that means 6^2+6^2=C^2
36+36=C^2
72=C^2
C≈ 8.485
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goblinko [34]

Answer:

-8/3 = d OR -2 2/3

Step-by-step explanation:

9d-4d-2d+8=-3d               Well first combine all like terms

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3d(-3d) + 8= -3d (-3d)

8= -3d                             Divide both sides by -3

-8/3 = d OR -2 2/3

6 0
3 years ago
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Hoochie [10]
Hi there
The formula you meant
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3 years ago
5x+3(x-1) = 8(x + 2) - 10
Levart [38]

Answer:

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8x-8x=9

= 9

5 0
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galben [10]
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