Area of the figure = 30.28 m²
Solution:
The given image is splitted into two shapes.
One is rectangle and the other is semi-circle.
Length of the rectangle = 6 m
Width of the rectangle = 4 m
Area of the rectangle = length × width
= 6 m × 4 m
= 24 m²
Area of the rectangle = 24 m²
Diameter of the semi-circle = 4 m
Radius of the semi-circle = 4 m ÷ 2 = 2 m
Area of the semi-circle = 


Area of the semi-circle = 6.28 m²
Area of the figure = Area of the rectangle + Area of the semi-circle
= 24 m² + 6.28 m²
= 30.28 m²
Area of the figure = 30.28 m²
Answer:
0.0105
Step-by-step explanation:
given that 30% of all houses need a paint job. Also, 15% of all houses need both a paint job and a new roof. Further, 7% of all houses that need a new roof also need new windows.
If total houses are 100, then 30 require a paint along. 15 require both paint and new roof.
Out of 15 houses which require new roof 7% need new windows
i.e. no of houses which need new windows = 
If there are total 100 houses, 1.05 houses require a new window
So probability that a randomly selectede house needs a new window
= 0.0105
I believe it would be 0 fr
Answer:
1). Because whole number doesn’t allow decimal numbers.
2). Because whole number doesn’t allow negative numbers. It starts with 0, 1, 2, 3....
1. C
2.D
3.A
4.B
Hope this helps!