A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o
n four randomly chosen students during the exam. What is the probability that he finds at least one of the students cheating
1 answer:
Answer:
6%
Step-by-step explanation:
3/20=4/x
It is a indirect proportion so we reciprocal,
Then,
3/20=x/40
3×40=20×x
120=20x
x=120/20
x=6
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![(\sqrt[5]{x^{7}})^{3}=(x^{\frac{7}{5}})^{3}=x^{\frac{7\cdot3}{5}}=x^{\frac{21}{5}}](https://tex.z-dn.net/?f=%28%5Csqrt%5B5%5D%7Bx%5E%7B7%7D%7D%29%5E%7B3%7D%3D%28x%5E%7B%5Cfrac%7B7%7D%7B5%7D%7D%29%5E%7B3%7D%3Dx%5E%7B%5Cfrac%7B7%5Ccdot3%7D%7B5%7D%7D%3Dx%5E%7B%5Cfrac%7B21%7D%7B5%7D%7D)
The root is equivalent to a fractional power with that number as the denominator. Otherwise, the rules of exponents apply.
