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3 years ago

) What is the area of triangle QBA? Enter only the number to represent the area below. plz i need the answer

Mathematics

1 answer:

olasank [31]3 years ago

8 0

Answer:

Step-by-step explanation:

Even though the triangle is "upside down"

a = (1/2)bh

b is QB = 4

h is QA = 7

a = (1/2) * 4 * 7

a = 14

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You have 5 pairs of pants, 8 shirts, and 3 ties - how many different outfits can you make?

SVEN [57.7K]

First they have to decide on a pair of pants and they have 8 different choices. For each of those choices they have a choice of 5 different shirts, so that gives them 8 times 5 = 40 different pant/shirt combinations. For each those 40 possibilities, they have 3 different ties they could select, so altogether they have 40 times 3 = 120 different outfits.

6 0

3 years ago

Expand 4(-2y+ 3).<br> 2y+7<br> 0:-8 y + 12<br> 2 y + 12<br> -8 y+ 3

stepan [7]

It is -8y+12
You have to multiply 4 by -2 which equals -8
Then you do 4x3 which equals 12

8 0

3 years ago

Which values of a, b, and c correctly represent the answer in simplest form? 6 al- o a=1,0-5,0-9 a= 10,5= 18.0= 1 a=9,0-5,0- 1 a

kumpel [21]

Answer:

The question is not explained well, Please explain it better or take a screenshot or something

Step-by-step explanation:

8 0

3 years ago

The average of six numbers is 4. If the of two of those numbers is 2, what is the average of the other four numbers?

matrenka [14]

Answer:

Step-by-step explanation:

total sum of the 6 numbers

= 4 ×6

= 24

sum of numbers without the two 2s

= 24 - 2(2)

= 20

average of other 4 numbers

= 20 ÷ 4

= 5

6 0

3 years ago

6.Suppose the Gallup Organization wants to estimate the population proportion of those who think there should be a law that woul

drek231 [11]

Answer:

A sample of $n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$ is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In a previous study of 1012 randomly chosen respondents, 374 said that there should be such a law.

This means that $n = 1012, \pi = \frac{374}{1012} = 0.3696$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

How large a sample size is needed to be 95% confident with a margin of error of E?

A sample size of n is needed, and n is found when M = E.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$E = 1.96\sqrt{\frac{0.3696*0.6304}{n}}$

$E\sqrt{n} = 1.96\sqrt{0.3696*0.6304}$

$\sqrt{n} = \frac{1.96\sqrt{0.3696*0.6304}}{E}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$

$n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$

A sample of $n = (\frac{1.96\sqrt{0.3696*0.6304}}{E})^2$ is needed, in which E is the desired margin of error, as a proportion. If we find a decimal value, we round up to the next whole number.

4 0

3 years ago