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borishaifa [10]
3 years ago
9

Ruby invested $850 in an account paying an interest rate of 2% compounded

Mathematics
1 answer:
swat323 years ago
8 0

Answer:

<em>To the nearest dollar, Logan would have $1 in his account more than Ruby</em>

Step-by-step explanation:

<u>Compound Interest</u>

It occurs when the interest is reinvested rather than paying it out.

Interest in the next period is then earned on the principal sum plus previously accumulated interest.

The formula is:

\displaystyle A=P\left(1+{\frac {r}{n}}\right)^{nt}

Where:

A = final amount

P = initial principal balance

r = interest rate

n = number of times interest applied per time period

t = number of time periods elapsed

Ruby invested P=$850 at r=2%=0.02 compounded quarterly. There are 4 quarts in a year, thus n=4. The investment lasted for t=17 years.

The final amount Ruby has is:

\displaystyle A=850\left(1+{\frac {0.02}{4}}\right)^{4*17}

A=850*1.40376

A=$1,193.19

------------------------------------------------------------------

Logan invested P=$850 at r=2%=0.02 compounded monthly. There are 12 months in a year, thus n=12. The investment lasted for t=17 years.

The final amount Logan has is:

\displaystyle A=850\left(1+{\frac {0.02}{12}}\right)^{12*17}

A=850*1,40455

A=$1,193.87

The difference is $0.67.

To the nearest dollar, Logan would have $1 in his account more than Ruby

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