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Anon25 [30]
3 years ago
13

Solve the system using substitution. Show your work. x = -4y + 9 x - y = 4

Mathematics
2 answers:
lesya692 [45]3 years ago
7 0
X = -4y + 9
x - y = 4

- rearrange the second equation to x = 4 + y
- then we can plug it into x for the first equation

4 + y = -4y + 9 — then we solve for y
y = -4y + 5
5y = 5 -> y = 1

we can then plug in 1 (our y value) into the original second equation.

x - 1 = 4 -> x = 5

x = 5 & y = 1
you should put it in a coordinate layout so:
(5,1)

hope this helped !!
FromTheMoon [43]3 years ago
6 0

Answer:

please what should we found? is it the value of ×or y

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KonstantinChe [14]

From the double-angle identity,

cos2x=2*sinx*cosx

we can rewritte our given equation as:

4sinxcosx-2cosx=0

By factoring 2cosx on the left hand side, we have

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This equation has 2 solutions when

\begin{gathered} cosx=0\text{ ...\lparen A\rparen} \\ and \\ 2sinx-1=0\text{ ...\lparen B\rparen} \end{gathered}

From equation (A), we obtain

x=\frac{\pi}{2}\text{ or }\frac{3\pi}{2}

and from equation (B), we have

\begin{gathered} sinx=\frac{1}{2} \\ which\text{ gives} \\ x=\frac{\pi}{6}\text{ or }\frac{5\pi}{6} \end{gathered}

On the other hand, we can find one more solution from the original equation by substituting x=0, that is,

\begin{gathered} 2ccos(2\times0)-2cos0=0 \\ which\text{ gives} \\ 2\times1-2\times1=0 \\ so\text{ 0=0} \end{gathered}

then, x=0 is another solution. In summary, we have obtained the following solutions:

\begin{gathered} x=0 \\ x=\frac{\pi}{2}\text{or}\frac{3\pi}{2}\text{ and } \\ x=\frac{\pi}{6}\text{or}\frac{5\pi}{6} \end{gathered}

However, the intersection of the last set is empty. So the unique solution is x=0 as we can corroborate on the following picture:

Therefore, the solution set is: {0}

7 0
1 year ago
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