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olasank [31]
3 years ago
5

You can get a quart bottle of cola for $1.50 or a liter bottle for $1.57. Which is the better buy in terms of price per volume?

Mathematics
1 answer:
pochemuha3 years ago
5 0

Answer:

The quart bottle of cola for $1.50 is the better buy.

Step-by-step explanation:

In order to compare the amount of cola per cost, you need to first use the same measurements.  Since one bottle is a quart and one bottle is a liter, we need to convert one to the other.  There are approximately 1.06 quarts per liter.  So, for the quart bottle, we can also say it has 1.06 liters of cola.  To find the price per volume, we take the cost divided by the volume:  1.50 ÷ 1.06 = $1.42.  The liter bottle costs $1.57.  So, the quart bottle would be cheaper overall by approximately $0.15.  

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There are 26 gold fish in the tank at the store. how many ways can ben choose 5?
Lapatulllka [165]

Answer:

5

Step-by-step explanation:

26/5= 5.2

the greatest whole number that can be chosen is 5.

6 0
3 years ago
Two garden plots are to have the same area. One is square and one is rectangular. The rectangular plot is 2 meters wide and 8 me
Crank

First, let's look at the formulas for the area of square and area of the rectangle.

A_{square}=a^2

A_{rectangle}=a\cdot b

And what this exercise states is that the areas are the same. So:

A_{square}=A_{rectangle}\Longrightarrow a^2=a\cdot b

Now put in the data.

a^2=2\cdot8

Solve for a:

a=\sqrt{2\cdot8}=\sqrt{16}=\boxed{4}

The side of the square garden plot is 4 meters.

Hope this helps.

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7 0
3 years ago
The producer of a certain bottling equipment claims that the variance of all its filled bottles is .027 or less. A sample of 30
o-na [289]

Answer:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

b. between .025 and .05

Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

\bar X represent the sample mean

n = 30 sample size

s= 0.2 represent the sample deviation

\sigma_o =\sqrt{0.027}=0.164 the value that we want to test

p_v represent the p value for the test

t represent the statistic

\alpha= significance level

State the null and alternative hypothesis

On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

H0: \sigma \leq 0.027

H1: \sigma >0.027

In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

t=(30-1) [\frac{0.2}{0.164}]^2 =42.963

What is the approximate p-value of the test?

The degrees of freedom are given by:

df=n-1= 30-1=29

For this case since we have a right tailed test the p value is given by:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

And the best option would be:

b. between .025 and .05

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Answer:

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