All categories

3 years ago

I need help on this question

Mathematics

1 answer:

Darina [25.2K]3 years ago

3 0

Answer:

B, D

Step-by-step explanation:

Since the number in parentheses has 1 + interest rate, subtract by 1 to find rate, which is 0.0325 or 3.25%.

Since the principal is multiplied by the parenthesis, $500 is the principal.

You might be interested in

A^2-2ab-6by+ay<br><br> Factor the expression

Angelina_Jolie [31]

Factor a^2−2ab−6by+3ay

a^2−2ab+3ay−6by

=(a−2b)(a+3y)

Answer:

(a−2b)(a+3y)

7 0

4 years ago

(0.4k3 – 2.5k) – (2.4k3 + 3k2 – 1.2k) =

Y_Kistochka [10]

Its –2k3<span> – 3k</span>2<span> – 1.3k that's what it is for sure</span>

3 0

3 years ago

Read 2 more answers

Two men walk at rates of 6 miles per hour and 10 miles per hour, respectively. Simultaneously, they started from the same place

alina1380 [7]

The time taken by the two men will be equal to 26 hours

<h3>What is speed?</h3>

The speed is defined as the ratio of the time distance traveled by the body to the time taken by the body to cover the distance.

here two men are walking at different speeds like

v₁=6 miles per hour

v₂=10 miles per hour

The time taken by them to separated by the distance of 100 miles each so that both of them separated by the distance of 200 miles.

t₁= {100}/{6}=16.66 hours

t₂= {100}/{10}=10 hours

total time taken will be

t₁+t₂=16.66+10=26.66 hours

To know more about Speed follow

brainly.com/question/6504879

#SPJ1

5 0

3 years ago

I need help on this problem!?

nata0808 [166]

156/4=39 miles per gallon. 39*12 gallons is 468 miles, and 6 gallons is 234.

6 0

4 years ago

Arrange the summation expressions in increasing order of their values.

nalin [4]

We'll solve for each one of them:

$\sum_{i=1}^{4}4(5)^{i-1} = (4(5)^{1-1}) + (4(5)^{2-1}) + (4(5)^{3-1}) + (4(5)^{4-1})$
$=4+20+100+500 = 624$

$\sum_{i=1}^{5}3(4)^{i-1} = (3(4)^{1-1}) + (3(4)^{2-1}) + (3(4)^{3-1}) + (3(4)^{4-1}) + (3(4)^{5-1})$
$=3+12+48+192+768=1023$

$\sum_{i=1}^{2}5(6)^{i-1} = (5(6)^{1-1}) + (5(6)^{2-1})$
$=5+30=35$

$\sum_{i=1}^{4}5^{i-1} = (5^{1-1})+(5^{2-1})+(5^{3-1})+(5^{4-1})$
$=1 + 5+ 25+125 = 156$

So, our totals are: 624, 1023, 35, and 156. So clearly, 1023 > 624 > 156 > 35. W can write it as (your answer):

$\sum_{i=1}^{2}5(6)^{i-1}$

Hope this helps! If anything is confusing, you can always DM me.

3 0

3 years ago

Read 2 more answers