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OleMash [197]
3 years ago
5

Your Assignment: Furry Friends

Mathematics
1 answer:
Levart [38]3 years ago
5 0

2. Create frequency tables to represent the morning and afternoon dogs as two sets of data. Group the weights into classes that range 10 pounds. (4 points: 2 points for appropriate intervals, 2 points for correctly portraying data)

Morning

Range

Dogs

10 to 19

3

20 to 29

4

30 to 39

3

Afternoon

Range

Dogs

0 to 9

2

10 to 19

3

20 to 29

1

30 to 39

2

40 to 49

1

50 to 59

1

3. What is the median of the morning (AM) group? What is the median of the afternoon (PM) group? (2 points: 1 point for each answer)

Morning (AM): 25.5

Afternoon (PM): 19

4. What is the first quartile (Q1) of the morning (AM) group? What is the first quartile (Q1) of the afternoon (PM) group? (2 points: 1 point for each answer)

Morning (AM): 10

Afternoon (PM): 0

5. What is the third quartile (Q3) of the morning (AM) group? What is the third quartile (Q3) of the afternoon (PM) group? (2 points: 1 point for each answer)

Morning (AM): 20

Afternoon (PM): 10

6. What is the interquartile range (IQR) of the morning (AM) group? What is the interquartile range (IQR) of the afternoon (PM) group? (2 points: 1 point for each answer)

Morning (AM): 39

Afternoon (PM): 29

7. The average weights of the dogs are the same for the morning and afternoon groups. But based on your comparative box plot and the IQRs of the two groups, which group of dogs does you think would be easier to walk as one group? Why? (2 points: 1 point for the answer, 1 point for justification)

The morning dogs, there are fewer dogs and they seem to weigh less.

All of the answers I have here!

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a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
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Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

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Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

M = \frac{1}{2}(Lower + Upper)

Where

Lower \to Lower class interval

Upper \to Upper class interval

So, we have:

Class 63-65:

M = \frac{1}{2}(63 + 65) = 64

Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

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