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damaskus [11]
4 years ago
11

What is greater. 3/5 or 1/4

Mathematics
2 answers:
choli [55]4 years ago
4 0

Answer:

1/4 is greater than 3/5.

Gnom [1K]4 years ago
4 0

Answer:

3/5

Step-by-step explanation:

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I need to turn this in! can anyone help ???
elixir [45]

Answer: It's (3,-2)

Step-by-step explanation:

5 0
3 years ago
How many flowers, spaced every 6 inches, are needed to surround a circular garden with a 10 foot radius?
Stolb23 [73]

To solve this problem you must apply the proccedure shown below:

1. You must calculate the perimeter of the circle:

The radius of the circle in inches is:

radius=\frac{(10ft)(12in)}{1ft}=120in

P=2\pi(radius)\\  P=2\pi(120in)\\ P=753.98in

2. Now, you must divide the perimeter by the space between each flower to find the number of flowers needed, which you can call x:

x=\frac{753.98in}{6in}=125.6=126

The answer is: 126 flowers.

5 0
3 years ago
How is the series 5+11+17…+251 represented in summation notation?
NISA [10]

Answer:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

Step-by-step explanation:

Given:

  • Series 5+11+17+...+251

To find:

  • Summation notation of the given series

Summation Notation:

\displaystyle \large{\sum_{k=1}^n a_k}

Where n is the number of terms and \displaystyle \large{a_k} is general term.

First, determine what kind of series it is, there are two main series that everyone should know:

  • Arithmetic Series

A series that has common difference.

  • Geometric Series

A series that has common ratio.

If you notice and keep subtracting the next term with previous term:

  • 11-5 = 6
  • 17-11 = 6

Two common difference, we can in fact say that the series is arithmetic one. Since we know the type of series, we have to find the number of terms.

Now that brings us to arithmetic sequence, we know that first term is 5 and last term is 251, we’ll be finding both general term and number of term using arithmetic sequence:

<u>Arithmetic Sequence</u>

\displaystyle \large{a_n=a_1+(n-1)d}

Where \displaystyle \large{a_n} is the nth term, \displaystyle \large{a_1} is the first term and \displaystyle \large{d} is the common difference:

So for our general term:

\displaystyle \large{a_n=5+(n-1)6}\\\displaystyle \large{a_n=5+6n-6}\\\displaystyle \large{a_n=6n-1}

And for number of terms, substitute \displaystyle \large{a_n} = 251 and solve for n:

\displaystyle \large{251=6n-1}\\\displaystyle \large{252=6n}\\\displaystyle \large{n=42}

Now we can convert the series to summation notation as given the formula above, substitute as we get:

\displaystyle \large{\sum_{n=1}^{42}(6n-1)

5 0
3 years ago
Which of the following equations is equivalent to b' = x?
vivado [14]

Answer:

It is A

Step-by-step explanation:

8 0
3 years ago
How do u do this ? I'm so confused I really need help
Art [367]
Well what do u need help with can u explain?
5 0
3 years ago
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