y=2/3y-3
1. y = 2/3 (9)-3 multiply 9 and 2 =18/3
y=18/3-3 divide 18 and 3 =6
y=6-3 subt. 3
y=3
2. -11=2/3x - 3
-11+3 = 2/3 x add 3 to both sides to cancel -3
-8=2/3 x
(3/2)-8 = (2/3)3/2 x multiply both sides by reciprical of 2/3
-24/2 = x divide
-12=x
C^2+(2/3)
2^2+(2/3)
4+(2/3)
4 2/3
Final answer: 4 2/3 or 14/3 as an improper fraction
12 goes into 75 6 times with a remainder of 3. So the answer will be 6 remainder 3
Answer:
h= x/ x+4
Step-by-step explanation:
Move all terms to the left side and set equal to zero, Then set each factor equal to zero.
Answer: 60
Step-by-step explanation:
Let the side lengths of the rectangular pan be m and n. It follows that (m-2) (n-2)=
So, since haf of the brownie pieces are in the interior. This gives 2 (m-2) (n-2) =mn
mn- 2m - 2n- 4 = 0
Then Adding 8 to both sides and applying, we obtain (m-2) (n-2) =8
Since now, m and n are both positive, we obtain (m,n) = (5,12), (6,8) (up to ordering). By inspection, 5. 12 = 60
which maximizes the number of brownies in total which is the greatest number.
Hope that helped! =)