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nikitadnepr [17]
2 years ago
13

Steve has a square patio with sides of length 9 feet. He plans to enlarge it to a rectangular patio by

Mathematics
1 answer:
Greeley [361]2 years ago
5 0

Answer:

51ft^2

Step-by-step explanation:

Given data

Side of square patio= 9ft

Area= 9*9= 81 ft^2

New length = 9+3= 12ft

New Widht = 9+2= 11ft

New Area= 12*11

New Area= 132ft^2

Hence the area added is

=132-81

=51ft^2

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What is c in 6c + 3y = 18 if y is 2?
Natali [406]

Answer:

c = 2

Step-by-step explanation:

6c + 3y = 18

6c + 3(2) = 18

6c + 6 = 18

6c = 12

c = 2

6 0
2 years ago
Read 2 more answers
Me podrían ayudar y explicarme el proceso please
kakasveta [241]

Answer: Encontrarás las respuestas debajo de cada explicación. Espero que consideres darme brainliest y 5 estrellas, y más importante, que hayas entendido.

Step-by-step explanation:

Esto es la regla de 3. Conoces 3 valores y necesitas encontrar un 4to valor.

Ya sabemos que 1 caja pesa 20kg,

1 - 20kg

ahora queremos saber cuantas cajas (x) equivalen a 7653kg

x - 7653kg

Hacemos un pequeño cuadro poniendo en un lado los numeros de cajas y del otro el peso.

Pongamos la cantidad de cajas en la izquierda y el peso en la derecha

\frac{1}{x} =\frac{20kg}{7653kg}

Procedemos a multiplicar en cruz. Solo podemos multiplicar si tenemos ambos valores. En este caso, los valores en cruz que tenemos son 1 y 7653kg porque en la otra cruz (20 y x) tenemos nuestra incognita. Y, por ultimo, dividimos entre el numero cuya cruz es con la incognita (20kg)

Esto nos deja la expresión así;

x=\frac{1*7653kg}{20kg}

x=382.65

Como una caja no puede ser un numero decimal, redondeamos.

x=383

Por lo tanto, se necesitan aproximadamente 383 cajas para que su peso equivalga a 7653 kg.

-------------------------------------------------------------------------------------------------------

La otra pregunta dice: Si una caja pesa 20kg, (1 - 20kg), ¿Cuántas cajas se necesitan para equivaler 9500kg? (x - 9500kg)

Hacemos lo mismo que arriba, ponemos la cantidad de cajas de un lado, y el peso de otro lado.

\frac{1}{x}=\frac{20kg}{9500kg}

Multiplicamos aquellos valores en cruz que conozcamos y dividimos por el valor cuya cruz sea con x.

x=\frac{1*9500kg}{20kg}

x=475

Esta es la cantidad de cajas que se necesitan para que su pesa equivalga a 9500kg.

--------------------------------------------------------------------------------------------------------

Por último, la pregunta dice, ¿Cuántos kilogramos hay en 873 cajas?

Ya sabemos que una caja pesa 20kg ( 1 - 20kg ) y ahora buscamos cuantos kg hay en 873 cajas; es decir, (873 - x)

Nos quedaría así;

\frac{1}{873}=\frac{20kg}{x}

Ahora, nuestra cruz es 873 y 20kg, y el divisor es 1.

x=\frac{873*20kg}{1}

x=17460kg

Este sería el peso de 873 cajas.

5 0
3 years ago
Which expression is a factor of 16x^2-81
krek1111 [17]

Answer:

b

Step-by-step explanation:

Reasoning: the square root of 16 is 4 and 81 square root is 9

so it is b pls give brainliest! have a good day

3 0
2 years ago
A theater has 40 seats in the first row, 43 seats in the second row, 46 seats in the third row, and so on. How many seats are th
iris [78.8K]
94 seats

There are 2 ways to do this one: 

1. 18 x 3 = 54
54 + 40 = 94

2. 40 + 3 + 3 + 3.... and so on. 



Let me know if this was helpful! 
4 0
3 years ago
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The average survival time after diagnosis for a certain type of cancer on the standard treatment is two years. A medical researc
wolverine [178]

Answer:

The sample size is too small

Step-by-step explanation:

The answer is the last one: the sample size is too small. Since we only got 3 subjects to test, maybe one of them could live for a long time after the diagnosis of Cacer and that made the average survival time go up by a lot.

In order to obtain results with a significance level higher, you need a sample size of at least 20 subjects.

Now lets see why other options wouldnt be good answers:

  • For a small amount of subjects, it is unlikely to have errors in caculation
  • The sample size is given
  • We are not given information about the treatment and we dont even know if the subjects feel more confident with the new treatment. Also, if a Placebo effect works regularly, it shouldnt limit statistical sifgnificance
  • An increase in 2 years is huge in comparison with the previous survival time.

4 0
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