3 years ago

Find the value of M, to the nearest tenth

Mathematics

2 answers:

jeka57 [31]3 years ago

8 0

Answer:

Step-by-step explanation:

a_sh-v [17]3 years ago

7 0

Answer:

m = 18*sin(43)

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Step-by-step explanation:

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How do you solve this in standard form. y=7x-4

attashe74 [19]

Y = 2/7x - 4
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4 = 2/7x - y (multiply everything by seven to get rid of the fraction)
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3 years ago

There are 9 female performers in a dance recital. The ratio of men to women is 2:3. How many men are in the dance recital?

Firdavs [7]

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Step-by-step explanation:

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3 years ago

A geometric series has second term 375 and fifth term 81 . find the sum to infinity of series .

Eduardwww [97]

Answer: $\bold{S_{\infty}=\dfrac{3125}{2}=1562.5}$

<u>Step-by-step explanation:</u>

a₁, 375, a₃, a₄, 81

First, let's find the ratio (r). There are three multiple from 375 to 81.

$375r^3=81\\\\r^3=\dfrac{81}{375}\\\\\\r^3=\dfrac{27}{125}\qquad \leftarrow simplied\\\\\\\sqrt[3]{r^3} =\sqrt[3]{\dfrac{27}{125}}\\ \\\\r=\dfrac{3}{5}$

Next, let's find a₁

$a_1\bigg(\dfrac{3}{5}\bigg)=375\\\\\\a_1=375\bigg(\dfrac{5}{3}\bigg)\\\\\\a_1=125(5)\\\\\\a_1=625$

Lastly, Use the Infinite Geometric Sum Formula to find the sum:

$S_{\infty}=\dfrac{a_1}{1-r}\\\\\\.\quad =\dfrac{625}{1-\frac{3}{5}}\\\\\\.\quad =\dfrac{625}{\frac{2}{5}}\\\\\\.\quad = \dfrac{625(5)}{2}\\\\\\.\quad = \large\boxed{\dfrac{3125}{2}}$

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Vikki [24]

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The answer is A

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