Answer:
Explanation:
2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s); ΔᵣH = ?
The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is
2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s)
ΔfH°/kJ·mol⁻¹: 0 -824.3 -1675.7 0
![\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [1(-1675.7) + 2(0)] - [2(0) - 1(-824.3)]\\& = & -1675.7 + 824.3\\& = & \textbf{-851.4 kJ/mol}\\\end{array}\\\text{The enthalpy change is } \large \boxed{\textbf{-851.4 kJ/mol}}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5CDelta_%7B%5Ctext%7Br%7D%7DH%5E%7B%5Ccirc%7D%20%26%20%3D%20%26%20%5B1%28-1675.7%29%20%2B%202%280%29%5D%20-%20%5B2%280%29%20-%201%28-824.3%29%5D%5C%5C%26%20%3D%20%26%20-1675.7%20%2B%20824.3%5C%5C%26%20%3D%20%26%20%5Ctextbf%7B-851.4%20kJ%2Fmol%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20enthalpy%20change%20is%20%7D%20%5Clarge%20%5Cboxed%7B%5Ctextbf%7B-851.4%20kJ%2Fmol%7D%7D)
C.) There are FIVE states of matter in total
Water is your answer!!!!!!!!!
Because the density of Octanol is less than 1.00 g/mL, the density of water, the octanol will rest on top of the water in the beaker. Octanol will be on the top, water will be on the bottom.
Answer:
to avoid iodine vapor from escaping.
Explanation:
This question is all about an experimental work on the determination of the distribution of iodine between waters and cyclohexane. To understand this question one has to understand the topic "Equilibrium" very well.
One important thing that must be noted in this question is for us to remember that water and cyclohexane are two immiscible liquids. So, when Iodine is added to the two solvents, the iodine dissolves in both water and cyclohexane to certain rate ands then to an equilibrium which is;
Kd = I₂[Cyclohexane]/ I₂[water]. ----------------------------------------[**].
There is a release of I⁻¹ From the added potassium iodide which helps in making sure that the iodine vapor does not escape. Thus, forming a tri-iodide ion.
