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ale4655 [162]
3 years ago
7

Helppppp i don’t know what to do

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
6 0

Answer:

the last one

Step-by-step explanation:

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Which of the following sets of numbers could be the lengths of the sides of a triangle? A. 12 in., 24 in., 48 in.B. 12 in., 6 in
bearhunter [10]
C. And it would be a equilateral
5 0
3 years ago
Read 2 more answers
Hi there! Sorry to bother you, but can someone help me out with this? (the number 7 to 10)
maksim [4K]

Answer:

7. <K = <R

8. PR = JK

9. <A = <X

10. TX = AB

For question 7, find the angle that looks the most similar to the angle in the question.

For question 8, since the sides (not the hyp.) are equal, PR will be equal to any of those two.

For question 9, the triangles are positioned differently, but it is the angle with two angle lines on it.

Lastly, for question 10, TX will be the same length as the shortest side in the corresponding triangle.

6 0
3 years ago
Five cubes are lined up to form a solid. The side lengths of the cubes are 1 ft, 2 ft, 3 ft, 4 ft, and 5 ft. What is the volume
sdas [7]
First, you find the volume of each individual cube, and then you add everything up.  

 1^3 +2^3+3^3+4^3 + 5^3 = 225 

hope this helped :)
3 0
4 years ago
A circle is centered at (-6,3) and has a radius of 11. Where does the point (3,-3) lie?
scZoUnD [109]

Answer:

Inside the circle

Step-by-step explanation:

Use the distance formula to find the distance between the center and the point.

d = √((x₁ − x₂)² + (y₁ − y₂)²)

d = √((-6 − 3)² + (3 − (-3))²)

d = √((-9)² + (6)²)

d = √(81 + 36)

d = √117

d ≈ 10.817

This is less than the radius of 11, so the point is inside the circle.

4 0
4 years ago
Anybody know the correct answer?
earnstyle [38]

Since \csc^2{x}=\frac{1}{\sin^2{x}} and \cot^2{x}=\frac{\cos^2{x}}{\sin^2{x}}, we can rewrite the right side of the equation as

\frac{1}{\sin^2{x}}-\frac{\cos^2{x}}{\sin^2{x}} =\frac{1-\cos^2{x}}{\sin^2{x}}

Using the identity \sin^2{x}+\cos^2{x}=1, we can subtract \cos^2{x} from either side to obtain the identity \sin^2{x}=1-\cos^2{x}

substituting that into our previous expression, the right side of our equation simply becomes

\frac{\sin^2{x}}{\sin^2{x}}=1

We can now write our whole equation as

3\tan^2{x}-2=1

Adding 2 to both sides:

3\tan^2{x}=3

dividing both sides by 3:

\tan^2{x}=1

\tan{x}=\pm1

When 0 ≤ x ≤ π, tan x can only be equal to 1 when sin x = cos x, which happens at x = π/4, and it can only be equal to -1 when -sin x = cos x, which happens at x = 3π/4

4 0
3 years ago
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