Answer:
The first four terms of the above sequence are 1, 6, 11, 16.
Step-by-step explanation:
A sequence is defined by the function f(n)=f(n-1)+5.
Where n represents the number of the term for n>1
First Put n = 2
f(2)=f(2-1)+5.
= f (1) + 5
= -4 + 5
= 1
Second Put n = 3
f(3)=f(3-1)+5.
= f (2) + 5
= 1 + 5
= 6
Third Put n = 4
f(4)=f(4-1)+5.
= f (3) + 5
= 6+ 5
= 11
Second Put n = 5
f(5)=f(5-1)+5.
= f (4) + 5
= 11 + 5
= 16
Therefore the first four terms of the above sequence are 1, 6, 11, 16.
Answer:
5a
2
+4ab+5b
2
Step-by-step explanation:
step 1. (((0-(4•(a2)))+3ab)+(12•(b2)))+(((9•(a2))+ab)-7b2)
step 2. (((0-(4•(a2)))+3ab)+(12•(b2)))+((32a2+ab)-7b2)
step 3.(((0-(4•(a2)))+3ab)+(22•3b2))+(9a2+ab-7b2)
step 4. (((0-(4•(a2)))+3ab)+(22•3b2))+(9a2+ab-7b2)
step 5. 5.1 Factoring 5a2 + 4ab + 5b2
It would be 725/1000 because u are 3 spaces after the decimal
Answer:
yes
Step-by-step explanation:
