Ask question

Ask question

All categories

3 years ago

11

I'm doing test corrections rn but I need to show the work for this answer. The problem is that the this doesn't show the work an

d I need it for full credit, can someone show me the work please?

1 answer:

BabaBlast [244]3 years ago

6 0

The two angles are corresponding angles, so they are congruent (due to the horizontal lines being parallel)

x+15 = 102

x+15-15 = 102-15 .... subtract 15 from both sides

x = 87

You might be interested in

Bob is on the school swim team and has practice 4 days per week. He has to practice twice per day, in the morning and in the eve

mylen [45]

Answer:

1h every morning

Step-by-step explanation:

3 0

2 years ago

Help help please please

gtnhenbr [62]

✽ Hello there! ✽

4x+9<21

Move all the constants (numbers) to the right, using the opposite operation:

4x<21-9

4x<12

Divide both sides by 4 to isolate x:

x<3

<h2>Therefore, x<3 ✔︎</h2>

Hope this helps!

~Just a felicitous girlie

#HaveASplendidDay

$SilentNature$

8 0

2 years ago

Solve the equation : 2x + 7 = 21 and find the value of x. Is 2x + 7 = 21 a first degree equation or not?

Paraphin [41]

Answer:

The proposed equation is solved as follows:

2X + 7 = 21

2X = 21 - 7

2X = 14

X = 14 / 2

X = 7

The value of X is 7.

A first degree equation is an algebraic equation in which each term is either a constant or a product of a fixed term on a single variable. Therefore, this equation is a first degree one, since it only has a single variable, which is X.

4 0

2 years ago

What is the solution set of the quadratic equation 8x2 +2x +1 =0?

Sidana [21]

$\displaystyle\\
 8x^2 +2x +1 =0\\\\
x_{12}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-2\pm \sqrt{2^2-4\cdot 8 \cdot 1}}{2\cdot 8}=\\\\
=\frac{-2\pm \sqrt{4-32}}{16}=\frac{-2\pm \sqrt{-28}}{16}=\frac{-2\pm \sqrt{4\cdot 7\cdot(-1)}}{16}=\\\\
=\frac{-2\pm 2i\sqrt{7}}{16}=\frac{-1\pm i\sqrt{7}}{8}= -\frac{1}{8}\pm \frac{\sqrt{7}}{8}i\\\\
x_1 = \boxed{-\frac{1}{8}+ \frac{\sqrt{7}}{8}i}\\\\
x_2 = \boxed{-\frac{1}{8}- \frac{\sqrt{7}}{8}i}\\\\
x_1,~x_2~\in \mathbb{C}$

4 0

3 years ago

I WILL GIVE YOU BRAINLIEST, AND 30 POINTS SO PLEASE HELP ME, IT'S URGENT!

IRINA_888 [86]

Answer:

<em>Answer is option</em><em> </em><em>b</em><em>)</em><em> </em>

<em> ${(x - 3)}^{2} + {(y - 4)}^{2} = 400$ </em>

<em>Your</em><em> </em><em>guess</em><em> </em><em>was</em><em> </em><em>right</em><em>.</em>

Step-by-step explanation:

$the \: question \: states \: that \: \\ distance \: between \: two \: points \: is \: 20 \: units \: \\ and \: the \: two \: points \: are \: (x,y) \: \: and \: \: (3 ,- 4) \\ distance \: formula \\ = \sqrt{ {(x1 - x2) }^{2} + {(y1 - y2)}^{2} } \\ on \: substituting \: the \: values \: in \: formula \\ 20 = \sqrt{ {(x - 3)}^{2} + {(y - ( - 4))}^{2} } \\ 20 = \sqrt{ {(x - 3)}^{2} + {(y + 4)}^{2} } \\ now \: squaring \: on \: both \: sides \\ 400 = {(x - 3)}^{2} + {(y + 4)}^{2} \\ hence \: the \: answer \: is \: option \: b)$

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

6 0

3 years ago