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3 years ago

Round 913,610 to nearest ten

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

7 0

913,610 it is the same number because 0 is less than 5 so you don't have to round the tens place up by one

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In a right triangle, angle φ has a tangent value of 1.40. The side adjacent to angle φ has a length of 9.0 inches. What is the l

charle [14.2K]

Answer:

b) 12.6 inches

Step-by-step explanation:

tangent is the ratio of the side opposite over adjacent, so if we let x= length of the opposite side, 1.40=x/9, x=12.6 inches

3 0

3 years ago

The upper-left coordinates on a rectangle are (-1, 4) left parenthesis, minus, 1, comma, 4, right parenthesis, and the upper-rig

Zanzabum

Answer:

Kindly refer to the attached images for the answer.

Step-by-step explanation:

Upper left coordinates of a rectangle are (-1, 4).

Upper right coordinates of the rectangle are (3, 4).

Perimeter of the rectangle = 24 units

Let A(-1, 4) and B(3, 4).

First of all, let us find the distance between the coordinates A and B.

Distance formula can be used to find the distance.

Distance formula:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Here, we have the following values:

$x_1 = -1 \\y_1 = 4\\x_2 = 3\\y_2 = 4$

$AB = \sqrt{(3-(-1))^2+(4-4)^2} = 4\ units$

$Perimeter = 2 (Length + Width)\\\Rightarrow 24 = 2 \times (AB + BC)\\\Rightarrow 24 = 2 \times (4 + BC)\\\Rightarrow BC = 8$

When we will move from point B to C, we will move downwards on y axis for a distance of 8 units therefore value of $x$ coordinate will be same.

Therefore coordinates of C (3, 4-8) i.e. C (3, -4)

When we will move from C to D, the x coordinate will decrease for 4 units.

D (3-4, -4) i.e. D (-1, -4)

Kindly refer to the attached images for the answer.

6 0

3 years ago

Read 2 more answers

Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa

iVinArrow [24]

Given:

Distance between two buildings = $3x^3- x^2 + 7x +100$ feet apart.

Distance between highway and one building = $2x^2 + 7x$ feet.

Distance between highway and second building = $x^3 + 2x^2 - 18$ feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

$W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)$

$W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18$

Combining like terms, we get

$W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)$

$W=2x^3-5x^2+0+118$

$W=2x^3-5x^2+118$

Therefore, the width point highway is $2x^3-5x^2+118$ .

8 0

3 years ago

If you invested $600 at 3% simple interest for 2 years, how much interest do you earn? Show work and answer in complete sentence

zzz [600]

Answer:

I would rather do the second option of which uses Compound interest that will give a profit of $47.85

Step-by-step explanation:

In this problem we will be exploring the two formulas

1. simple interest

A= P(1+r*t)

2. compound interest

A= P(1+r/n)^nt

Where A= final amount

P= initial amount

r= rate

t= time.

n= number of periods Compounded

1.given data

P= $600

r= 3%= 3/100= 0.03

t= 2 years

A= 600(1+0.03*2)

A= 600(1+0.06)

A= 600(1.06)

A= $636

Interest = 636-600= $36

2. Given data

P= $600

r= 4%= 4/100= 0.04

n= 24

t= 2

A= 600(1+0.04/24)^24*2

A=600(1+0.0016)^48

A=600(1.0016)^48

A= 600*1.07975

A= 647.85

Interest = 647.85-600= $47.85

7 0

3 years ago

Solve for x. Enter the solutions from least to greatest. 2x^2– 5 = 13

frosja888 [35]

Answer:

x1 = -3 x2 = 3

Step-by-step explanation:

5 0

3 years ago