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Nadya [2.5K]
2 years ago
7

Hose bought 1.5 pounds of apples for $3.60 how much would 3/4 of a pound of apples cost

Mathematics
1 answer:
jasenka [17]2 years ago
4 0

\bf \begin{array}{ccll} \stackrel{apples}{lbs}&\$\\ \cline{1-2} 1.5&3.6\\[1em] \frac{3}{4}&x \end{array}\implies \cfrac{1.5}{~~\frac{3}{4}~~}=\cfrac{3.6}{x}\implies \cfrac{1.5}{1}\cdot \cfrac{4}{3}=\cfrac{3.6}{x}\implies \cfrac{6}{3}=\cfrac{3.6}{x} \\\\\\ 2=\cfrac{3.6}{x}\implies 2x=3.6\implies x=\cfrac{3.6}{2}\implies x=1.8

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Solve the following equation, using the Bhaskara formula: x² - 5x + 6 = 0
kramer

    x^2-5x+6=0

    x=\frac{-(-5)\pm\sqrt{(-5)^2-4\times1\times6}}{2\times1}\Leftrightarrow

\Leftrightarrow x=\frac{5\pm\sqrt{25-4\times6}}{2}\Leftrightarrow

\Leftrightarrow x=\frac{5\pm\sqrt{25-24}}{2}\Leftrightarrow

\Leftrightarrow x=\frac{5\pm\sqrt{1}}{2}\Leftrightarrow

\Leftrightarrow x=\frac{5\pm1}{2}\Leftrightarrow

\Leftrightarrow x=\frac{5-1}{2}\;\;\;\vee\;\;\;x=\frac{5+1}{2}\Leftrightarrow

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\Leftrightarrow x=2\;\;\;\vee\;\;\;x=3

Answer:  x\in\{2\;;\;3\}

4 0
3 years ago
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Suppose we want to choose 4 colors, without replacement, from 18 distinct colors.
amm1812

Answers:

  • (a) 73440
  • (b)  3060

=====================================================

Explanation for part (a)

Consider four slots labeled A,B,C,D.

We have

  • 18 choices for slot A
  • 17 choices for slot B
  • 16 choices for slot C
  • 15 choices for slot D

We started at 18 and counted down until we filled the four slots. The countdown is because we cannot repeat a color. Multiply out those values to get the answer: 18*17*16*15 = 73440

You can use the nPr permutation formula as an alternative method

_nP_r = \frac{n!}{(n-r)!}

in this case n = 18 and r = 4. The exclamation marks indicate factorial.

-----------------------------------

Explanation for part (b)

Let's say we had color labels A,B,C,... all the way up to R which is the 18th letter in the English alphabet. From those 18 letters, we can only pick four. Let's say we pick D,E,F,G.

Focusing solely on the set {D,E,F,G}, we only have one set and the order doesn't matter. So {D,E,F,G} is the same as {D,E,G,F}.

There are 4*3*2*1 = 24 ways to arrange those four items meaning that we'll need to divide the result of part (a) by 24 to get the result of part (b)

73440/24 = 3060

You could use the nCr combination formula to get the same result

_nC_r = \frac{n!}{r!(n-r)!}

where n = 18 and r = 4 are the same from last time.

The connection between nPr and nCr is this

_nC_r = \frac{_nP_r}{r!}

which can be rearranged into

_nP_r = r!*\left( _nC_r \right)

these formulas are handy to help us go back and forth between nCr or nPr.

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2 years ago
What is the value of x in the situation 5 1/6x + 2 1/4 =10
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Answer:

x=5/57

Step-by-step explanation:

(5/6x)+(1/2)=10

x=5/57

6 0
3 years ago
Simplify 5(5t+6)+2 (2t-3)
yan [13]

Answer:

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Step-by-step explanation:

5(5t + 6) + 2(2t - 3)

Open Parentheses first.

5* 5t = 25t

5 * 6 = 30

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Open others

2 * 2t = 4t

2 * 3 = 6

25t + 30 + 4t - 6

Match like terms

29t + 24

8 0
3 years ago
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