Write an equation for the line passing through the points (0,3) and (-9,0) using Y=mx+b format.

Mathematics

1 answer:

Valentin [98]3 years ago

7 0

Answer:

y = $\frac{1}{3}$ x + 3

Step-by-step explanation:

y = mx + b

y = mx + 3 (the y-intercept was given (0,3))

$\frac{3 - 0}{0 + 9}$ = $\frac{3}{9}$ = $\frac{1}{3}$

y = $\frac{1}{3}$ x + 3

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Perpendicular to y=4x-7; contains the point (4,3)

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Okay, so a general rule for finding perpendicular lines in the form of y = mx + b is y = (-1/m) + b.
First, let's ignore b (-7) because we're going to find that later.
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Alright, so now let's plug in the values. They are in the form of (x,y), so let's plug them in accordingly.

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3 = -1 + b
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