The equations used to find the measure of each angle in degrees is x + y = 90 and x = 6y - 1
The two complementary angles are 77 degrees and 13 degrees
<em><u>Solution:</u></em>
Given that two angles are complementary angles
Complementary angles are two angles whose sum is 90 degrees
Let one of the angle be "x" and the other angle be "y"
Therefore,
x + y = 90 ------ eqn 1
Also given that,
One angle is one less than six times the measure of another
one angle = six times the other angle - 1
x = 6y - 1 ------ eqn 2
Substitute eqn 2 in eqn 1
6y - 1 + y = 90
Thus the above equation is used to find the measure of each angle in degrees
Solve the above equation
6y + y - 1 = 90
7y - 1 = 90
7y = 91
y = 13
Substitute y = 13 in eqn 2
x = 6(13) - 1
x = 78 - 1
x = 77
Thus the two complementary angles are 77 degrees and 13 degrees
Answer:
h(x - 1) = -5x - 2
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Terms/Coefficients
Functions
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
h(x) = -5x - 7
<u>Step 2: Find</u>
- Substitute in <em>x </em>[Function h(x)]: h(x - 1) = -5(x - 1) - 7
- [Distributive Property] Distribute -5: h(x - 1) = -5x + 5 - 7
- Combine like terms: h(x - 1) = -5x - 2
Answer:
6:30
1:5
4:20
3:15
2:10
Step-by-step explanation:
im pretty sure these are correct
The variation of K is what is found in front of X
