1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
saw5 [17]
3 years ago
13

please help i am doing a test. Explain how you can use partial quotients to divide 7,563 ÷ 4 = ________.

Mathematics
1 answer:
Elza [17]3 years ago
6 0

Answer:

1890.75

so this is the answer to your question  

You might be interested in
A single year on Saturn is equal to 29.4 years on earth. About how many earth years are equal to 3.2 years on Saturn
-Dominant- [34]

1 year on Saturn = 29.4 years on Earth.

3.2 * 29.4 = 94.08

94.08 years on Earth are equal to 3.2 years on Saturn.

:)

5 0
3 years ago
Given: Q = 7m + 3n, R = 11 - 2m, S = n + 5, and T = -m - 3n + 8.
Oxana [17]

Answer:

6m + n + 2

Step-by-step explanation:

[7m + 3n - 11 - 2m] + [n + 5 - -m - 3n + 8]

[5m + 3n - 11] + [n + 5 + m - 3n + 8]

5m + 3n - 11 + (-2n + 13 + m)

5m + 3n - 11 - 2n + 13 + m

6m + n + 2

3 0
3 years ago
13-0.75w+ 8x when w = 12and x =1/2
Oksi-84 [34.3K]

Answer:

9

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
( 20points please ) -22+(-16)=
hjlf

-22+(-16)

-22-16= -38

5 0
4 years ago
Read 2 more answers
here are several types of objects. For each type of object, estimate how many there are in a stack that is 5 feet high. Be prepa
lorasvet [3.4K]

We need to estimate how tall is, on average, one of these object, and then count how many would be in a 5 feet high stack.

For example, on Google you may see that "1.5 cubic foot boxes are the standard box, manufactured by most companies". So, we assume that a standard cardboard box is 1.5 feet tall.

So, if we set the equation

1.5k = 5 \iff k=\dfrac{5}{1.5}=3.\bar{3}

So, there would be between 3 and 4 cardboard boxes in a 5 feet tall stack.

Similarly, we can see that the average book is 9 inches tall. 9 inches are 0.75

feet, so we have

0.75k=5 \iff k=6.\bar{6}

So, there would be between 6 and 7 books in a 5 feet tall stack.

The average brick is 75 millimeters tall, which means 0.25 feet tall. Again, we have

0.25k=5 \iff k=20

So, there would be 20 bricks in a 5 feet tall stack.

Finally, a coin is about 0.006 feet, which leads to

0.006k=5 \iff k=833.\bar{3}

So, there would be between 833 and 834 coins in a 5 feet tall stack.

5 0
3 years ago
Other questions:
  • if a florist is making identical bouquets using 72 red roses 60 pink roses and 48 yellow roses what is the greatest number of bo
    15·2 answers
  • a 6lb watermelon costs $2.40 before a 30% discount. Which equation would allow you to find the discounted price of the watermelo
    14·1 answer
  • What is 164.50 rounded.
    11·1 answer
  • Is 4.78778777... a rational or irrational​ number?
    15·1 answer
  • Find the sum or difference: <br><br> -(2-x)-3(6+8x)-12<br><br> Please solve
    7·1 answer
  • An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you th
    14·1 answer
  • Square root of 7 hole 18/49​
    7·2 answers
  • The diameter of a circle is 3 cm. Find the circumference and the area.
    8·1 answer
  • Hello :) <br> Please help me solve this <br><br> Explain answer
    6·1 answer
  • Solve the Inequality. Graph the solution. <br><br> n+2 less than or equal to sign -6
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!