Answer:
2.5 miles
Step-by-step explanation:
The relation between time, speed, and distance is ...
distance = speed × time
We can define t to be Stanley's swimming time. Then t+0.5 was his running time, and 2(t+0.5) was his biking time. His total distance covered is ...
64 = 9(t +0.5) +16(2(t +0.5)) +2.5(t)
64 = 43.5t +20.5 . . . . . . . simplify
43.5 = 43.5t . . . . . . . . . subtract 20.5
t = 1 . . . . . . . . . . . . . . divide by the coefficient of t
Stanley swam for 1 hour, so the distance he covered while swimming was ...
(2.5 mi/h)(1 h) = 2.5 mi
Stanley covered 2.5 miles while swimming.
_____
<em>Additional comment</em>
Stanley ran for 1.5 hours, covering 9×1.5 = 13.5 miles. He biked for 3 hours, covering 16×3 = 48 miles. His total distance was 2.5 +13.5 +48 = 64 miles, as given.
First add 13.2 to both sides to get 0.5x > 0.1x + 33.2.
Then subtract 0.1x from both sides to get 0.4x > 33.2.
Lastly, divide each side by 0.4 to get a final answer of x > 83.
Hope this helps!
Bob gets 16 problems correct. Hope this helped.
Logbx+logby-logbz
=logb(x*y)/z if b is the base of log.
There are two properties that you can apply to get the correct answer.
logb(x*y)=logbx+logby if b is the base of log.
logb(x/y)=logbx-logby if b is the base of log, so the correct answer for logbx+logby-logbz=logb(x*y)/z. Hope it help!
