0 box 36 singles
1 box 26 singles
2 boxes 16 singles
3 boxes 6 singles
Answer:
c<1
Step-by-step explanation:
Less than 1.
Answer:
On-time Buses: 75%
Running late Buses: 13.46%
Step-by-step explanation:
Part 1: Solve for the probability of Jerry owning an "on-time" bus
Of the 48 buses that run on time, Jerry owns 36 of them. Therefore, the probability of a bus running on time being owned by Jerry will be solved with the ratio of 36 buses to 48 buses.
- This is represented by the fraction 36/48.
- Simplifying this fraction will give us 3/4.
- Convert to a decimal and then multiply by 100 to get a percentage - 75%.
Part 2: Solve for the probability of Jerry owning a "running late" bus
Of the 52 buses that run late, Jerry owns 7 of them. Therefore, the probability of a bus running late & being owned by Jerry will be solved with the ratio of 7 buses to 52 buses.
- This is represented by the fraction 7/52.
- Simplifying this fraction will give us 7/52 (cannot be simplified).
- Convert to a decimal and then multiply by 100 to get a percentage - 13.46%.
3 hours because all u do is subtract 5 hours and 8 hours and
Answer:
The equations that represent the reflected functions are
![f(x)=5(\frac{1}{5})^{-x}](https://tex.z-dn.net/?f=f%28x%29%3D5%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B-x%7D)
![f(x)=5(5)^{x}](https://tex.z-dn.net/?f=f%28x%29%3D5%285%29%5E%7Bx%7D)
Step-by-step explanation:
The correct question in the attached figure
we have the function
![f(x)=5(\frac{1}{5})^{x}](https://tex.z-dn.net/?f=f%28x%29%3D5%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7Bx%7D)
we know that
A reflection across the y-axis interchanges positive x-values with negative x-values, swapping x and −x.
therefore
![f(−x) = f(x).](https://tex.z-dn.net/?f=f%28%E2%88%92x%29%20%3D%20f%28x%29.)
The reflection of the given function across the y-axis will be equal to
(Remember interchanges positive x-values with negative x-values)![f(x)=5(\frac{1}{5})^{-x}](https://tex.z-dn.net/?f=f%28x%29%3D5%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B-x%7D)
An equivalent form will be
![f(x)=5(\frac{1}{5})^{(-1)(x)}=5[(\frac{1}{5})^{-1})]^{x}=5(5)^{x}](https://tex.z-dn.net/?f=f%28x%29%3D5%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B%28-1%29%28x%29%7D%3D5%5B%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B-1%7D%29%5D%5E%7Bx%7D%3D5%285%29%5E%7Bx%7D)
therefore
The equations that represent the reflected functions are
![f(x)=5(\frac{1}{5})^{-x}](https://tex.z-dn.net/?f=f%28x%29%3D5%28%5Cfrac%7B1%7D%7B5%7D%29%5E%7B-x%7D)
![f(x)=5(5)^{x}](https://tex.z-dn.net/?f=f%28x%29%3D5%285%29%5E%7Bx%7D)