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s344n2d4d5 [400]
3 years ago
11

Jacob went camping with his family. At 7:15 A.M., Jacob set out to go fishing. It took 1 hour and 45 minutes to hike to the lake

. Jacob spent 3 hours and 45 minutes fishing, and it took 1 hour and 15 minutes to hike back. What time was it when Jacob got back to camp?
Include A.M. or P.M. in your answer Please help me fast!!,
Mathematics
2 answers:
Verizon [17]3 years ago
4 0
The answer is 2 P.M.
nekit [7.7K]3 years ago
4 0
Jacob returned at 2PM
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Answer:

12

Step-by-step explanation:

4 x 3 is 12

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Please help no links
Nina [5.8K]

Answer:

x=5 y=-6

Step-by-step explanation:

3x+y=9 ------eqn1

y=4-2x -------eqn2

using substitution

put y=4-2x into eqn1

3x+4-2x=9

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What is 3 root of 27
daser333 [38]
It is 3.

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4 0
3 years ago
Can you help me find t value in this problem?
Eduardwww [97]

we have a maximum at t = 0, where the maximum is y = 30.

We have a minimum at t = -1 and t = 1, where the minimum is y = 20.

<h3>How to find the maximums and minimums?</h3>

These are given by the zeros of the first derivation.

In this case, the function is:

w(t) = 10t^4 - 20t^2 + 30.

The first derivation is:

w'(t) = 4*10t^3 - 2*20t

w'(t) = 40t^3 - 40t

The zeros are:

0 = 40t^3 - 40t

We can rewrite this as:

0 = t*(40t^2 - 40)

So one zero is at t = 0, the other two are given by:

0 = 40t^2 - 40

40/40 = t^2

±√1 = ±1 = t

So we have 3 roots:

t = -1, 0, 1

We can just evaluate the function in these 3 values to see which ones are maximums and minimums.

w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20

w(0) = 10*0^4 - 20*0^2 + 30    = 30

w(1) =  10*(1)^4 - 20*(1)^2 + 30 =  20

So we have a maximum at x = 0, where the maximum is y = 30.

We have a minimum at x = -1 and x = 1, where the minimum is y = 20.

If you want to learn more about maximization, you can read:

brainly.com/question/19819849

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2 years ago
The volume of this rectangle prism=____ft3.
serious [3.7K]

Answer:

18

Step-by-step explanation:

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