Answer:
7.5
Step-by-step explanation:
Answer:
95.15%
Step-by-step explanation:
We have that the mean (m) is equal to 20, the standard deviation (sd) 3
They ask us for P (x <25)
For this, the first thing is to calculate z, which is given by the following equation:
z = (x - m) / sd
We have all these values, replacing we have:
z = (25 - 20) / (3)
z = 1.66
With the normal distribution table (attached), we have that at that value, the probability is:
P (z <1.66) = 0.9515
Which means that the probability that it arrives before 25 minutes is 95.15%
Answer:
1/4
Step-by-step explanation:
The chance of it landing heads up once would be 1/2
The chance of it landing heads up twice would be 1/4
The chance of it landing heads up three times would be 1/8
The chance of it landing heads up four times would be 1/16
See the pattern?
Pattern: <em><u>Divide the denominator by 2.</u></em>
<h2>
<em>Please give brainliest!!! :) </em></h2>
What is the question you are asking and no one is gonna know what lesson 3.2 means.
Let's assume two variables x and y which represent the local and international calls respectively.
x + y = 852 = total number of minutes which were consumed by the company (equation 1)
0.06*x+ 0.15 y =69.84 = total price which was charged for the phone calls (Equation 2)
from equation 1:-
x=852 -y (sub in equation 2)
0.06 (852 - y) + 0.15 y =69.84
51.12 -0.06 y +0.15 y =69.84 (subtracting both sides by 51.12)
0.09 y =18.74
y= 208 minutes = international minutes (sub in 1)
208+x=852 (By subtracting both sides by 208)
x = 852-208 = 644 minutes = local minutes
