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Paul [167]
3 years ago
11

Find the value of "k", given that one solution of the equation x2-kx+21=0 is 3

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0
Plug in 3 for x and solve for k.
(3)^2-3k+21=0
3k=9+21
3k=30
k=10
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Help please! I'm stuck with all these numbers :(
yuradex [85]

Answer:

C

Step-by-step explanation:

8 0
3 years ago
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A chess board is an 8 by 8 grid of squares. If you randomly choose 3 squares on the board, what is the probability that:
bixtya [17]
The answer is the letter B
3 0
3 years ago
Question 6 of 15
umka2103 [35]

Answer:

LE=5\ units

Step-by-step explanation:

we know that

In a rectangle, the two diagonals are congruent and each diagonal bisects the other

so

LN=2KE ----> equation A

KE=LE -----> equation B

step 1

Find the value of x

solve equation A

LN=2KE

substitute the given values

(2x+2)=2(3x-7)

solve for x

2x+2=6x-14\\6x-2x=2+14\\4x=16\\x=4

step 2

Find the value of KE

KE=3x-7

substitute the value of x

KE=3(4)-7=5\ units

Remember that

KE=LE  -----> by each diagonal bisects the other

therefore

LE=5\ units

8 0
3 years ago
Write an equation of the line that passes through the given point and is parallel to the given line.
9966 [12]

Answer : <em>Equation of line is</em> y=Equation of line is y=\frac{2}{3}x+\frac{-5}{3}

Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y = \frac{2}{3}x+1 is m= \frac{2}{3}

We know that line : y = \frac{2}{3}x+1 is parallel to equation of target line.

therefore, slope of target line will be \frac{2}{3}.

we write equation of target line as y= \frac{2}{3}x+c

Now, It is given that target line passes through point ( -5,-2)

hence, point ( -5,-2) satisfy the target line's equation.

we get,

y= \frac{2}{3}x+c

-2= \frac{2}{3} \times -5+ c

-5= \frac{-10}{3}+c

c= \frac{-5}{3}

thus, Equation of line is y=Equation of line is y=\frac{2}{3}x+\frac{-5}{3}

7 0
3 years ago
A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec
VMariaS [17]

Answer:

19.1-3.355\frac{1.5}{\sqrt{9}}=17.42    

19.1+3.355\frac{1.5}{\sqrt{9}}=20.78    

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=19.1 represent the sample mean

\mu population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=9-1=8

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that t_{\alpha/2}=

Now we have everything in order to replace into formula (1):

19.1-3.355\frac{1.5}{\sqrt{9}}=17.42    

19.1+3.355\frac{1.5}{\sqrt{9}}=20.78    

And the best option would be:

C. [17.42,20.78]

5 0
3 years ago
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