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garik1379 [7]
3 years ago
14

Point T is on line segment

Mathematics
1 answer:
oksian1 [2.3K]3 years ago
3 0

Answer:

Im bored

Step-by-step explanation:

Thanks for scamming me cause I never would have got points this easy

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Solve the equation 58 - 10x ≤ 20 + 9x
drek231 [11]

Answer:

x≥2

Step-by-step explanation:

First, write out the equation as you have it:

58-10x\leq20+9x

Then, add 10x to both sides:

58-10x+10x\leq20+9x+10x\\58\leq20+19x

Next, subtract 20 from both sides:

58-20\leq20-20+19x\\38\leq19x

Finally, divide both sides by 19:

\frac{38}{19}\leq\frac{19x}{19}\\2\leq x

or

x\geq 2

Therefore: the answer to this inequality/equation is: x≥2

6 0
3 years ago
Which statements describe America’s workforce during World War II? Check all that apply.
soldier1979 [14.2K]

Step-by-step explanation:

hundreds of thousands of women signed up for the US military

5 0
3 years ago
Read 2 more answers
PLEASE HELP! I have a deadline tonight ,I have to get this done! thank you!!<br> Two questions (:
Viktor [21]
Both of your answers are correct. In the first equation, if you were to substitute 3 for x, because you have to do exponents first, you have 3^2, which is 9, and 9*6 =54. If you were to substitute -3 for x again you would have to do the exponents first which would be -3^2 which is 9, and 9*6 = 54. 

For the second question, if I substitute 0.75 for t, I get -9 + 18 + 7. This is equal to 16, and therefore the answer would be D. Hope this helps! :D. Let me know if you have questions about my explanation, and feel free to post more questions.
3 0
3 years ago
How to solve this ? I am not sure pls if you know the answer answer it I really neeed it for marks
xz_007 [3.2K]

Answer:

L.S = R.S ⇒ Proved down

Step-by-step explanation:

Let us revise some rules in trigonometry

  1. sin²α + cos²α = 1
  2. sin2α = 2 sin α cosα
  3. cscα = 1/sinα

To solve the question let us find the simplest form of the right side and the left side, then show that they are equal

∵ L.S = csc2α + 1

→ By using the 3rd rule above

∴ L.S = \frac{1}{sin2\alpha} + 1

→ Change 1 to \frac{sin2\alpha}{sin2\alpha}

∴ L.S = \frac{1}{sin2\alpha} + \frac{sin2\alpha}{sin2\alpha}

→ The denominators are equal, then add the numerators

∴ L.S = \frac{1+sin2\alpha}{sin2\alpha}

∵ R. S = \frac{(sin\alpha+cos\alpha)^{2} }{sin2\alpha}

∵ (sinα + cosα)² = sin²α + 2 sinα cosα + cos²α

∴ (sinα + cosα)² = sin²α + cos²α + 2 sinα cosα

→ By using the 1st rule above, equate sin²α + cos²α by 1

∴ (sinα + cosα)² = 1 + 2 sinα cosα

→ By using the 2nd rule above, equate 2 sinα cosα by sin2α

∴ (sinα + cosα)² = 1 + sin2α

→ Substitute it in the R.S above

∴ R. S = \frac{1+sin2\alpha}{sin2\alpha}

∵ L.S = R.S

∴ csc 2α + 1 = \frac{(sin\alpha+cos\alpha)^{2} }{sin2\alpha}

4 0
3 years ago
During​ spring, young​ moose, unfamiliar with roads and​ traffic, are wandering around at night in a​ province, causing risk and
34kurt
Answer: A not b
Because it’s just not
3 0
3 years ago
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