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erik [133]
3 years ago
6

F(x) = 3x3 - 5x2 +6x -12

Mathematics
1 answer:
arlik [135]3 years ago
7 0

Answer:

1.79438504

Step-by-step explanation:

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2 (5y-4)&gt;32<br> Solve the inequality for y.
scoray [572]

Answer:

y > 4

Step-by-step explanation:

2 (5y-4)>32

Divide each side by 2

2/2 (5y-4)>32/2

5y-4 > 16

Add 4 to each side

5y-4+4 > 16+4

5y > 20

Divide each side by 5

5y/5 > 20/5

y > 4

5 0
3 years ago
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Solve 0 = (x – 4)2 – 1 by graphing the related function.
fomenos

Answer:

Therefore, the solutions of the quadratic equations are:

x=5,\:x=3

The graph is also attached.

Step-by-step explanation:

The solution of the graph could be obtained by finding the x-intercept.

y=\left(x-\:4\right)^2-1

Finding the x-intercept by substituting the value y = 0

so

y=\left(x-\:4\right)^2-1

\:0\:=\:\left(x\:-\:4\right)^2\:-\:1        ∵ y = 0

\left(x-4\right)^2-1=0

\left(x-4\right)^2-1+1=0+1

\left(x-4\right)^2=1

\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

\mathrm{Solve\:}\:x-4=\sqrt{1}

\mathrm{Apply\:rule}\:\sqrt{1}=1

x-4=1

x=5

\mathrm{Solve\:}\:x-4=-\sqrt{1}

\mathrm{Apply\:rule}\:\sqrt{1}=1

x-4=-1

x=3

So, when y = 0, then x values are 3, and 5.

Therefore, the solutions of the quadratic equations are:

x=5,\:x=3

The graph is also attached. As the graph is a Parabola. It is visible from the graph that the values of y = 0 at x = 5 and x = 3. As the graph is a Parabola.

8 0
3 years ago
some friends need 100 bows for a project Sara brings 12 bows Angela brings 50 bows and Nora brings 34 bows how many more bows do
Irina-Kira [14]
They need 4 more because 12+50+34=96 96-100 is 4 hope this helps ya
7 0
3 years ago
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14x² - 21x³ + 49x⁴<br><br>ayudenme porfavor​
Ad libitum [116K]

no se

sólo lo hago esto para poder preguntar

7 0
2 years ago
What percent of $200 is $40?
forsale [732]
To find the answer to the question we do the equation 40/200*100

Which gets us our answer of 20%
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3 years ago
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