Answer:
x = -1
Step-by-step explanation:
Since the line is completely vertical there is no slope.
When a line is completely vertical, the setup is x = ___ (fill in the blank with the number that the line intersects on the x axis, in this case -1.)
When a line is completely horizontal (not applicable in this problem) the setup is y = ___ (fill in the blank with the number the line intersects on the y axis.)
We know that
Two angles are said to be co-terminal <span>if they have the same initial side and </span>
<span>the same terminal side.
</span>
(52π/5)-----> 10.4π<span>
so
</span>(52π/5)-5*2π------> (2π/5)
the answer is
the positive angle less than one revolution around the unit circle that is co-terminal with angle of 52π/5 is 2π/5
Answer:
- The sum of the series is given as
7/(1 + 7z)
- The series converges for (-1/7, 1/7)
Step-by-step explanation:
Given the geometric series:
7 - 14z + 28z² - 56z³ + ...
The common ratio r is given as
-14z/7 or 28z²/(-14z) or -56z³/(28z²) and so on
r = -7z
The sum of the series is given as
S = a/(1 - r)
Where a is the first term in the series.
S = 7/(1 -(-7z))
= 7/(1 + 7z)
The series converges for |-7z| < 1
That is for -1/7 < z < 1/7
Answer: I need a picture off the pool and measurements.
Step-by-step explanation: I need this in order to figure out the problem and give you a helpful answer.
Answer:
y = 50x+25
f(x) = 50x+25
Step-by-step explanation:
Using the slope intercept form of the equation, y = mx+b
where x is the amount per day and b is the flat fee
2 days
125 = 2x+b
5 days
275 = 5x+b
Subtract
275 = 4x+b
125 = 2x+b
---------------------
150 = 3x
Divide by 3
150/3 = 3x/3
50 =x
The cost per day is 50 dollars
y = 50x +b
Using the data for 2 days
125 = 50*2 +b
125 = 100 +b
125-100 = b
b = 25
The equation is y = 50x+25
f(x) = 50x+25
To graph, The x axis is number of days and the y axis is total cost
The number of days starts with 0, which is the y intercept
Let x = 0, y =25
Using the slope, we go 50 up and 1 to the right ( 50 dollars per day)
The next point plotted ins ( 1,50)
Draw a straight line
