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3 years ago

Please help me do number 5

Mathematics

1 answer:

Blizzard [7]3 years ago

7 0

Make more sense ou of this question and I can help you out more ok?

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Which system has no solutions?

Lapatulllka [165]

$\left\{\begin{array}{ccc}y \ \textgreater \ 6\\y \ \textless \ 2\end{array}\right\\\\\text{Look at the picture}$

3 0

3 years ago

The area of a rectangle is 45 cm2. Two squares are constructed such that two adjacent sides of the rectangle are each also the s

Zielflug [23.3K]

Answer:

The lengths of sides of squares are 5 cm and 9 cm.

Step-by-step explanation:

Let the sides of rectangle be x and y .

Area of rectangle = Length × Breadth

Given : Area of rectangle = 45 cm².

⇒ x × y = 45

⇒ $x=\frac{45}{y}$ ........(1)

Two squares are constructed such that two adjacent sides of the rectangle

so squares have side x and y .

Area of square = side × side

Area of square with side x = x²

Area of square with side y = y²

Also, The combined area of the two squares is 106 cm².

⇒ x² + y² = 106

From (1) put value of x , we get,

$(\frac{45}{y})^2+y^2=106$

Solving for y ,

$(\frac{45}{y})^2+y^2=106$

$2025+y^4=106y^2$

$y^4-106y^2+2025=0$

$y^4-81y^2-25y^2+2025=0$

$y^2(y^2-81)-25(y^2-81)=0$

$(y^2-25)(y^2-81)=0$

$y^2-81=0$ or $y^2-25=0$

on solving we get y = 5 and y = 9

Also, x can be find by putting in (1),

⇒ $x=\frac{45}{5}=9$ and ⇒ $x=\frac{45}{9}=5$

⇒ x = 9 and x = 5

Thus, lengths of sides of squares are 5 cm and 9 cm.

6 0

3 years ago

Read 2 more answers

138.4divided by16 show works it possible to show your work

Lorico [155]

Ok done. Thank to me :>

4 0

2 years ago

An adult brain is about 140 mm wide and divided into two sections (called "hemispheres" although the brain is not truly spherica

Sedbober [7]

Answer: 3.61×10^5 A

Step-by-step explanation: Since the brain has been modeled as a current carrying loop, we use the formulae for the magnetic field on a current carrying loop to get the current on the hemisphere of the brain.

The formulae is given below as

B = u×Ia²/2(x²+a²)^3/2

Where B = strength of magnetic field on the axis of a circular loop = 4.15T

u = permeability of free space = 1.256×10^-6 mkg/s²A²

I = current on loop =?

a = radius of loop.

Radius of loop is gotten as shown... Radius = diameter /2, but diameter = 65mm hence radius = 32.5mm = 32.5×10^-3 m = 3.25×10^-2m

x = distance of the sensor away from center of loop = 2.10 cm = 0.021m

By substituting the parameters into the formulae, we have that

4.15 = 1.256×10^-6 × I × (3.25×10^-2)²/2{(0.021²) + (3.25×10^-2)²}^3/2

4.15 = 13.2665 × 10^-10 × I/ 2( 0.00149725)^3/2

4.15 = 1.32665 ×10^-9 × I / 2( 0.000058)

4.15 × 2( 0.000058) = 1.32665 ×10^-9 × I

I = 4.15 × 2( 0.000058)/ 1.32665 ×10^-9

I = 4.80×10^-4 / 1.32665 ×10^-9

I = 3.61×10^5 A

3 0

3 years ago

Noah says to find 20% of a number he divides the number by 5. Is this true explain your answer

Nutka1998 [239]

Answer:

yes

Step-by-step explanation:

note that 20% = $\frac{20}{100}$ = $\frac{1}{5}$

Hence to find 20% of a number, dividing the number by 5 is correct

20% of £30 = $\frac{30}{5}$ = £6

5 0

3 years ago