The surface area of the composite figure is 714 sq. in.
<h3>What is formula of surface area of cube ?</h3>
Let, a be the edge of the cube.
Then, surface area of the cube = 6a² square unit
<h3>What is formula of surface area of cuboid ?</h3>
Let, length of the cuboid = l unit
Width of the cuboid = w unit
Height of the cuboid = h unit
Then, surface area of the cuboid = 2(lw+lh+hw) square unit
<h3>What is the required surface area ?</h3>
Given, edge of cube = 4 in.
∴ Surface area of cube = (6×4²) sq. in. = 96 sq. in.
Now, given, length of cuboid = 15 in.
Width of the cuboid = 10 in. & height of the cuboid = 7 in.
∴ Surface area of the cuboid = 2{(15×10)+(15×7)+(10×7)} sq. in.
= 2{150+105+70} sq. in.
= 2{325} sq. in. = 650 sq. in.
Here, we have to find the surface area of the composite figure.
We have to subtract the surface area from both of cube & cuboid, where they are attached.In that case, we have to subtract (4×4) from both.
So, we have to subtract 2(4×4) sq. in. = 32 sq. in.
∴ The surface area of the composite figure = (650+96-32) sq. in.
= 714 sq. in.
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