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amm1812
3 years ago
12

The sum of two numbers is 51 and the greater number is twice the smaller number. Find the numbers.

Mathematics
1 answer:
Kruka [31]3 years ago
7 0

Answer:

34 and 17

Step-by-step explanation:

x+y=51

2y=x

2y+y=51

3y=51

y=17

2(17)=x

x=34

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Which equation is rewritten in vertex form?
Zinaida [17]
(x + 3)^2 + (x + 4)^2 
= x^2 + 6x + 9 + x^2 + 8x + 16
= 2x^2 + 14x + 25
= 2(x^2 + 7x) + 25
= 2[(x + 7/2)^2  - 49/4] + 25
= 2(x + 7/2)^2 - 98/4 + 25
= 2(x + 7/2)^2 + 1/2


Its B

7 0
3 years ago
What is the answer to this
skad [1K]
The answer is 10 because 5 and 5 is 10
8 0
3 years ago
2. A student usually saves $20 per month. He would like to reach a goal of saving $350 in 12 months. The student writes the equa
Zigmanuir [339]

Answer:

x = 9.17 (nearest hundredth)

The variable x is the amount the student needs to save each month in addition to his usual saved amount of $20.

Step-by-step explanation:

350 = 12(x + 20)

Multiply out brackets:  350 = 12x + 240

Subtract 240 from both sides:  110 = 12x

Divide both sides by 12:  9 1/6 = x

x = 9.17 (nearest hundredth)

The variable x is the amount the student needs to save each month in addition to his usual saved amount of $20.

3 0
2 years ago
HELPP!!what is the answer to this picture above^
nasty-shy [4]

Answer:

\fbox{ \fbox { \sf{Distance  =  \sf{15 \: units}}}}

{ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}

Step-by-step explanation:

\star{ \:  \sf { \: Let \: the \: points \: be \: A \: and \: B}}

\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}

\underline{ \underline{ \tt{Finding \: the \: distance}}}

\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(18 - 6)}^{2}  +  {(15 - 6)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{ {(12)}^{2}  +  {(9)}^{2} } }}

\mapsto{ \sf{Distance =  \sqrt{144 + 81}}}

\mapsto{ \sf{Distance =  \sqrt{225} }}

\mapsto{ \sf{Distance =  \sqrt{ {15}^{2} } }}

\mapsto{  \boxed{\sf{Distance = 15 \: units}}}

\underline{ \underline {\tt{Finding \: the \: Midpoint}}}

\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2}  \: , \:  \frac{y1 + y2}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2}  \: , \:  \frac{6 + 15}{2} )}}

\mapsto{ \sf{Midpoint = ( \frac{24}{2}  \: , \:  \frac{21}{2} )}}

\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}

Hope I helped!

Best regards! :D

~\sf{TheAnimeGirl}

3 0
3 years ago
Suppose a pack of candy bars has 4 bars. Each bar weighs 3.38 ounces. How much does the pack weigh?
drek231 [11]

Answer:

13.52 ounces I think...

Step-by-step explanation:

4x3.38 subtract the decimal and add it again...

5 0
3 years ago
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