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3 years ago

Find the midpoint of A and B where A has coordinates (-7, 1) and B has coordinates (3,-5).

Mathematics

1 answer:

zepelin [54]3 years ago

3 0

Answer:

A (-7, 1) = (X1, Y1)

B (3, -5) = (X1, Y2)

Now,

Mid point = (X1 + X2÷2, Y1 + Y2 ÷ 2)

= {-7+3÷2, 1+(-5)÷2}

= (-4÷2, 1-5÷2)

= (-4÷2, -4÷2)

= (-2, -2)

Step-by-step explanation:

I hope it will help you to study.

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Bart ran 5000 from the cop and an average speed of 6 meters/ seconds before he got caught. how long did he run?

Masja [62]

Answer:

13.8 minutes

Step-by-step explanation:

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3 years ago

Devisibility rules for 3, 6, and 9

fenix001 [56]

Answer:

★ Divisibility rule for 3 -

If the sum of all the digits divisible by 3 then the number is divisible by 3.

Here, we take an example for better understanding -

Example 1 - 3525

Add up the digits - 3 + 5 + 2 + 5

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As, 15 is divisible by 3. So, 3525 is a factor of 3.

★ Divisibility rule for 6 -

A number is to be divisible by 6 , if the number is also divisible by 2 and 3.

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Add up the digits = 1 + 3 + 2 = 6

As, 6 is divisible by 2 and it's also divisible by 3. Then, 132 is a factor of 6.

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If the sum of all the digits is divisible by 9 then the number is divisible by 9. Just like we'd in 3.

Example 3 - 1052

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As, 17 is not divisible by 9. So, 1052 is also not divisible by 9.

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3 years ago

Express 23/7 in decimal form

g100num [7]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

One number is 16 more than a second number. The sum of the first number and twice the second number is 139. What is the answer ?

Nezavi [6.7K]

Answer first number = 57 second number = 41
x= 16 + y
x + 2y = 139

16+ y + 2y =139
16 + 3y =139
16-16 +3y = 139-16
3y = 123
3/3y = 123/3
y= 41

x= 16+y
x = 16+41
x= 57

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3 years ago