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taurus [48]
3 years ago
13

I need help with one question. anyone pls?

Mathematics
2 answers:
denpristay [2]3 years ago
7 0

Answer:

(-3,4)......... multiply the first equation by the coefficient of y i.e 3 (of 2nd equation)...

again multipy the 2nd eq by the coefficient of y i.e 2 (of 1st eq)

and finally solve the eq 3 and 4 ...(solve the both eq formed by multiplying)

oksano4ka [1.4K]3 years ago
4 0

Answer:

(-3,4)

Step-by-step explanation:

x + 2y = 5

-3 + (2*4) = 5

-3 + 8 = 5

5 = 5

2x + 3y = 6

(2*-3) + (3*4)=6

-6 + 12 = 6

6 = 6

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Solve the given system of equations.<br> - 3a = 36<br> 10a + 3c = 9<br> 2b + 50 = 23
Elodia [21]

Answer:

Solve using the substitution method! Answer down below:)

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5 0
3 years ago
In an arithmetic sequence, if you are given a3=93 and a5=135, find a=100. Must show work to receive full credit.
Elanso [62]

The 100th term of the sequence is 2130.

<h3>How to calculate the value?</h3>

a3 = a + 2d = 93

a5 = a + 4d = 135

Compute both equations

(4d - 2d) = (135 - 93)

2d = 42

d = 42/2 = 21

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= a + 99d

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