Answer:
d.0.48
Explanation:
When a population is in Hardy Weinberg equilibrium the <u>genotypic </u>frequencies are:
freq (AA) = p²
freq (Aa) = 2pq
freq (aa) = q²
<em>p</em> is the frequency of the dominant <em>A</em> allele and <em>q</em> is the frequency of the recessive <em>a</em> allele.
In this population of 100 individuals, 84 martians have the dominant phenotype and 16 have the recessive phenotype.
Therefore:
q²=16/100
q² = 0.16
q=√0.16
q = 0.4
And p+q=1, so:
p = 1 - q
p = 1-0.4
p = 0.6
The frequency of heterozygotes is:
freq (Aa) = 2pq = 2 × 0.4 × 0.6
freq (Aa) = 0.48
The pH of stomach secretion is low. This means it is acidic. Too much production can corrode the stomach wall. Therefore in such a situation drinking a basic solution with a higher pH neutralizes some of the stomach acidic secretions hence relieving the effect;
Acid + Base - Salt + Water
Explanation:
<em>Characteristics</em><em> </em><em>are</em><em> </em><em>as</em><em> </em><em>under:</em>
<em>1</em><em>.</em><em> </em><em>Living</em><em> </em><em>things</em><em> </em><em>respire.</em><em>.</em><em>.</em>
<em>2.</em><em> </em><em>Living </em><em>things</em><em> </em><em>can</em><em> </em><em>move</em><em>.</em><em>.</em>
<em>3</em><em>.</em><em> </em><em> </em><em>M</em><em>a</em><em>de </em><em>uo</em><em> </em><em>of</em><em> </em><em>cells</em><em>.</em><em>.</em>
<em>4</em><em>.</em><em> </em><em>Can</em><em> </em><em>Reproduce</em><em>.</em><em>.</em>
<em>5</em><em>.</em><em> </em><em>They</em><em> </em><em>carry</em><em> out</em><em> </em><em>various</em><em> </em><em>Life</em><em> </em><em>pr</em><em>o</em><em>cesses.</em><em>.</em><em>.</em>
Answer:
Answer and Explanation: Three codons are needed to specify three amino acids. Codons can be described as messengers that are on the messenger RNA (mRNA). It is a sequence of three nucleotides that code for one specific amino acid; therefore, every three nucleotides represent one codon.
Explanation: