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3 years ago

Desktop and personal computer are also known as

Computers and Technology

1 answer:

m_a_m_a [10]3 years ago

4 0

They are also known as general computers

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Lil fun question : burgers or pizza??

Margarita [4]

Pizza. . . . . . . . . . .

6 0

3 years ago

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Consider the two computers A and B with the clock cycle times 100 ps and 150 ps respectively for some program. The number of cyc

Kipish [7]

Answer:

Option d) B is 1.33 times faster than A

Given:

Clock time, $t_{A} = 100 ps$

$t_{A} = 150 ps$

No. of cycles per instructions, $n_{A} = 2.0$

$n_{B} = 1.0$

Solution:

Let I be the no. of instructions for the program.

CPU clock cycle, $f_{A}$ = 2.0 I

CPU clock cycle, $f_{B}$ = 1.0 I

Now,

CPU time for each can be calculated as:

CPU time, T = $CPU clock cycle\times clock time$

$T_{A} = f_{A}\times t_{A} = 2.0 I\times 100 = 200 I ps$

$T_{B} = f_{B}\times t_{B} = 1.0 I\times 100 = 150 I ps$

Thus B is faster than A

Now,

$\frac{Performance of A}{Performance of B} = \frac{T_{A}}{T_{B}}$

$\frac{Performance of A}{Performance of B} = \frac{200}{150}$

Performance of B is 1.33 times that of A

7 0

3 years ago

Read 2 more answers

XYZ Corp.’s facilities in Nashua, New Hampshire, are two office buildings 400 feet apart, each with its own LAN. To connect the

damaskus [11]

Answer:

a: Twisted pair won't span a 400-foot distance.

Explanation:

The maximum distance that twisted pair cables can support without attenuation is 100 meters which is approximately 328 feet and the two office buildings are 400 feet apart, so it is useless to install a twisted pair cable for such a large distance. A much better option would be to install optic fiber. Though it is a bit expensive but it is the best option in this case.

Hence option (a) is the correct reason for installing an optic fiber cable rather than a twisted pair cable.

6 0

3 years ago

Find the propagation delay for a signal traversing the in a metropolitan area through 200 km, at the speed of light in cable (2.

Ede4ka [16]

Answer:

t= 8.7*10⁻⁴ sec.

Explanation:

If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.

As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.

Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

$v = \frac{(xf-xo)}{(t-to)}$