To solve for the time an object takes to hit the ground, the equation
<em>y</em> <em>= y₀ + v₀t + ½gt²</em>, or just <em>0 = y₀ +½gt²</em> since there is no initial velocity and the final y position is 0 (since it is on the ground). Therefore, <em>t = (−2y₀/g)^½.</em>
(-2*60/-9.8)^½ = 3.50 seconds.
<em />
Step-by-step explanation:
4x 3.5 + 4x 2.3
14 + 9.2
= 23.2
Answer:
Step-by-step explanation:
- If f(x) is in th form of f(x)=g(x)-h(x) then f'(x)=g'(x) - h'(x)
- When f(x)=z(g(x)) then f'(x)= z'(g(x))g'(x) (called as chain rule)
<u>using these information</u>:
g(x)=ln2x then g'(x)=
h(x)=In(3x - 1) then h'(x)=![\frac{(3x-1)'}{3x-1} =\frac{3}{3x-1}f'(x)=g'(x) - h'(x) =[tex]\frac{1}{x} - \frac{3}{3x-1} =\frac{-1}{3x^2-x}](https://tex.z-dn.net/?f=%5Cfrac%7B%283x-1%29%27%7D%7B3x-1%7D%20%3D%5Cfrac%7B3%7D%7B3x-1%7D%3C%2Fp%3E%3Cp%3Ef%27%28x%29%3Dg%27%28x%29%20-%20h%27%28x%29%20%3D%5Btex%5D%5Cfrac%7B1%7D%7Bx%7D%20-%20%5Cfrac%7B3%7D%7B3x-1%7D%20%3D%5Cfrac%7B-1%7D%7B3x%5E2-x%7D)
The answer is 21.
First you Add both AB and BC which is 10x +14. Then you put 64 into the equation. 10x+14=64. Subtract 14 from 64 which is 50. So 10x=50. Then divide 10 from 50. which would be x=5. So if you plug it in. It would be 21.
