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NemiM [27]
3 years ago
11

Describe how to solve problems for the area of a reduced or enlarged figure when the scale factor and dimensions of the original

figure are given.
i wll give a brainliest out if it is correct plz hurry im on a quiz help
Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0

Answer:We are going to define the following variables:

A: Area of the original figure.

k: scale factor.

We have that the area of the new figure (reduced or enlarged, depends on the value of k) is:

A '= k ^ 2 * A

Example: rectangle of dimensions (2) * (3) A factor of k = 2 is extended. Find the new area.

The original area is:

A = (2) * (3) = 6

The new area will be:

A '= (2 * 2) * (2 * 3) = 4 * 6 = 24

Or equivalently:

A '= k ^ 2 * A

A '= (2) ^ 2 * (6) = 4 * 6 = 24

saw5 [17]3 years ago
5 0
I don’t understand the question
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<em>answer:</em>

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<em>Solution</em><em>,</em>

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<em>Height </em><em>of </em><em>tank=</em><em>1</em><em>.</em><em>9</em><em> </em><em>m</em>

<em>Given </em><em>tank </em><em>has </em><em>top </em><em>and </em><em>bottom </em>

<em>Now,</em><em> </em><em>The </em><em>total </em><em>surface </em><em>area </em><em>of </em><em>cylinder </em><em>tank </em><em>is </em><em>given </em><em>by:</em>

<em>tsa = 2\pi \:  {r}^{2}  + (2\pi \: r \: ) \times h</em>

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<em>TSA </em><em>Of </em><em>3</em><em> </em><em>tanks</em>

<em>=</em>

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<em>Given </em><em>a </em><em>tin </em><em>of </em><em>plate </em><em>covers </em><em>5</em><em>m</em><em>^</em><em>2</em><em> </em><em>area.</em>

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<em>x </em><em>tin</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em><em>4</em><em>.</em><em>3</em><em> </em><em>m^</em><em>2</em>

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