Do the area of the circle as a whole minus (72/360 x radius^2) and then minus the other grey area.
Hi there!


We can evaluate using the power rule and trig rules:



Therefore:
![\int\limits^{12}_{2} {x-sin(x)} \, dx = [\frac{1}{2}x^{2}+cos(x)]_{2}^{12}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B12%7D_%7B2%7D%20%7Bx-sin%28x%29%7D%20%5C%2C%20dx%20%3D%20%5B%5Cfrac%7B1%7D%7B2%7Dx%5E%7B2%7D%2Bcos%28x%29%5D_%7B2%7D%5E%7B12%7D)
Evaluate:

Answer:
The answer is -2 & 3
Step-by-step explanation:
Without seeing the picture, we don't know how DE and UV are related.
Answer:
Australia.
Bangladesh.
England.
India.
New Zealand.
South Africa.
Sri Lanka.
West Indies.
Step-by-step explanation:
none
hope this helps