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Brums [2.3K]
3 years ago
15

Which ordered pair maximizes the objective function p = 3x 8y?(0, 0)(2, 7)(5, 6)(8, 1)

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
3 0
A: 3•0 + 8•0 = 0 
<span>B: 3•2 + 8•7 = 62 </span>
<span>C: 3•5 + 8•6 = 63 </span>
<span>D: 3•8 + 8•1 = 32 </span>

<span>The ordered pair in selection C gives the highest value of P.</span>
sergey [27]3 years ago
3 0

Answer:

The correct answer is C . (5,6)

Step-by-step explanation:


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grandymaker [24]

Answer:

Step-by-step explanation:

2^(4/3) = 2.52

16^(1/3) (which is how you enter cube root of 16) = 2.52

4 0
3 years ago
Within the set of whole numbers , one set of numbers satisfies the recursive formula an=(an-1)^2-an-1, when a4=870 what are the
andrew11 [14]

Answer: 3 and 6 will be the first and second term of the given series respectively.

Explanation:  since it is given-  a_n=(a_{n-1} )^2-a_{n-1} and a_4=870

so, by replacing n by 4, we will get- a_4=a_3^2-a_3⇒870= a_3^2-a_3⇒ a_3^2-a_3-870=0

after solving this equation we will get, a_3= -29 and 30.

If a_3= -29, but it is not a whole number.

Thus,a_3=30 will be the value of third term of the given series.

Again, by applying the given condition a_n=(a_{n-1} )^2-a_{n-1}, a_2= 6 or -5 (not possible), so, a_2=6 will be the second term.

Similarly, a_1=3 or -2 but  we will go to the whole number.

Thus, a_1=3 will be the first term.

8 0
3 years ago
Read 2 more answers
Can someone help me solve this system of linear equations by the addition method?
schepotkina [342]
4x-8y=4
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3 0
3 years ago
Given that tan0= -1, what is the value of sec0, for 3pi/2&lt;0&lt;2pi?
Maru [420]

Answer: Choice B. sqrt(2)

Draw out a right triangle in quadrant IV as you see in the attached image below. The horizontal and vertical legs are both 1 unit long. To ensure that the signs are properly set up, I am making the vertical leg BC have a label "-1" to mean this is below the x axis. Note how

tan(theta) = opposite/adjacent = BC/AB = -1/1 = -1

Use the pythagorean theorem to find that the hypotenuse AC is sqrt(2) units long

a^2 + b^2 = c^2

(1)^2 + (1)^2 = c^2

2 = c^2

c^2 = 2

c = sqrt(2)

The secant of theta is the ratio of the hypotenuse over the adjacent side, so we end up with

sec(theta) = hypotenuse/adjacent

sec(theta) = AC/AB

sec(theta) = sqrt(2)/1

sec(theta) = sqrt(2) which is why choice B is the answer

7 0
3 years ago
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Vera_Pavlovna [14]

Answer:

25

Step-by-step explanation:

2x=x+25

2x-x=25

x=25

5 0
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