Answer:
990 ways to choose 6 starters out of 14 with exactly two of the three triplets.
Step-by-step explanation:
Ways to choose 2 of the triplets
= C(3,2) = 3! / (2!1!) = 3
Ways to choose the remaining 4 starters out of 11 players left
= C(11,4) = 11! / (4!7!) = 330
Total number of ways to choose 6 starters
= 3*330 = 990
Y = -2x + 4
6x + 3y = 6x + 3(-2x + 4) = 6x - 6x + 12 = 12
⇒ y = -2x + 4 == 6x + 3y = 12 ⇒ invinite solutions: 12
⇒ no solutions -12, -4, 0, 4
60 miles because (20mph)((3hrs) = 60
