We can find the surface area of the pyramid as
![A = l*w+l*\sqrt{(\frac{w}{2} )^{2} +h^{2} }+w*\sqrt{(\frac{l}{2} )^{2} +h^{2}}](https://tex.z-dn.net/?f=A%20%3D%20l%2Aw%2Bl%2A%5Csqrt%7B%28%5Cfrac%7Bw%7D%7B2%7D%20%29%5E%7B2%7D%20%2Bh%5E%7B2%7D%20%7D%2Bw%2A%5Csqrt%7B%28%5Cfrac%7Bl%7D%7B2%7D%20%29%5E%7B2%7D%20%2Bh%5E%7B2%7D%7D)
here , because the base is squre so
![l = w = 8](https://tex.z-dn.net/?f=l%20%3D%20w%20%3D%208)
![h = 5](https://tex.z-dn.net/?f=h%20%3D%205)
By putting the values of l,w and h
we get
![A = 8*8+8*\sqrt{(\frac{8}{2} )^{2} +5^{2} }+8*\sqrt{(\frac{8}{2} )^{2} +5^{2}}](https://tex.z-dn.net/?f=A%20%3D%208%2A8%2B8%2A%5Csqrt%7B%28%5Cfrac%7B8%7D%7B2%7D%20%29%5E%7B2%7D%20%2B5%5E%7B2%7D%20%7D%2B8%2A%5Csqrt%7B%28%5Cfrac%7B8%7D%7B2%7D%20%29%5E%7B2%7D%20%2B5%5E%7B2%7D%7D)
![A = 64+8*\sqrt{16 +25 }+8*\sqrt{16 +25}](https://tex.z-dn.net/?f=A%20%3D%2064%2B8%2A%5Csqrt%7B16%20%2B25%20%7D%2B8%2A%5Csqrt%7B16%20%2B25%7D)
![A = 64+(8*\sqrt{41) +(8*\sqrt{41})](https://tex.z-dn.net/?f=A%20%3D%2064%2B%288%2A%5Csqrt%7B41%29%20%2B%288%2A%5Csqrt%7B41%7D%29)
![A = 64+51.2+51.2](https://tex.z-dn.net/?f=A%20%3D%2064%2B51.2%2B51.2)
![A = 166.4](https://tex.z-dn.net/?f=A%20%3D%20166.4)
Answer:
5= 13.5
6=24.3
Step-by-step explanation:
s o/h, c a/h, t o/a
Answer:
i would add
Step-by-step explanation:
Answer:
1/4 , B
Step-by-step explanation:
This is because it is being kept on multiplying by 1/4 for each pattern.
Answer:
252 in^3
Step-by-step explanation:
8 * 2 * 7 plus 4 * 7 *5