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Otrada [13]
3 years ago
5

What is the equation of a line that is perpendicular to -x + 2y =4 and passes through the point (-2, 1)

Mathematics
1 answer:
Trava [24]3 years ago
8 0

Answer:

y = -2x - 3

Step-by-step explanation:

-solve for y: y = 1/2x + 2

-perpendicular equals opposite slope: -2

-plug in the point: (1) = -2(-2) + b

                               1 = 4 + b

                                b = -3

put it all together: y = -2x - 3

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__

b) The axis of symmetry for quadratic ax^2 +bx +c is x = -b/(2a). For this quadratic, that is x=-10/(2(-1)) = 5. This is the horizontal distance to the point of maximum height. The maximum height is ...

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Read 2 more answers
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