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2 years ago

Someone do these please!

Mathematics

1 answer:

IgorLugansk [536]2 years ago

7 0

Answer:

4). A) .20 , .194 B) the Cost-Co price is better 5) A) 476.991 , 479.99

B) 10% is better

Step-by-step explanation:

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Samira buys a car the car loses 23% of its value in the first year. at the end of the first year her car is worth 6575.80 dollar

Andreyy89

Answer: Samira paid $8540 for her car.

Step-by-step explanation:

Let x = Amount paid by Samira for her car.

Given: Depreciation rate = 23%

Worth of car after one year = $ 6575.80

As per given,

x - 23 % of x = 6575.80

⇒ x - 0.23x = 6575.80

⇒ 0.77x= 6575.80

⇒ x= $8540 [Divide both sides by 0.77]

Hence, Samira paid $8540 for her car.

6 0

3 years ago

Kelsey made 9 3/5 pounds of Chex mix. If she puts 4 4/5 pounds into each bag, how many bags can Kelsey fill?

vichka [17]

9.6/4.8= 2

Kelsey can fill 2 bags of Chex mix.

Hope this helps!

3 0

3 years ago

Problemas de razonamiento división de números decimales. Ayer Susana se fue de viaje a visitar a unos familiares. Recorrió 135,7

schepotkina [342]

Usando las relaciones entre velocidad, distancia y tiempo, se encuentra que ella condujo a una velocidad media de 90,5 km/h.

--------------------------

La velocidad es la distancia dividida por el tiempo, por lo que:

$v = \frac{d}{t}$

Total de 135,75 km, o sea, $d = 135,75$
Llego en 1,5 horas, o sea, $t = 1,5$

La velocidad es:

$v = \frac{d}{t} = \frac{135,75}{1,5}$

División de decimales, o sea, seguimos multiplicando los números por 10 hasta que ninguno sea decimal:

$v = \frac{135,75}{1,5} = \frac{1357,5}{15} = \frac{13575}{150} = 90,5$

Ella condujo a una velocidad media de 90,5 km/h.

Un problema similar es dado en brainly.com/question/24558377

4 0

2 years ago

Tara is trying to solve the following equation 4.5x-4=14

Romashka-Z-Leto [24]

Answer:

$4.5x - 4 = 14 \\ 4.5x = 14 + 4 \\ 4.5x = 18 \\ x = \frac{18}{4.5} \\ x = 4$

8 0

2 years ago

Read 2 more answers

Need help please help me

ANTONII [103]

Megan:
x to the one third power = $x ^{1/3}$
x to the one twelfth power = $x ^{1/12}$

The quantity of x to the one third power, over x to the one twelfth power is:
 $\frac{x ^{1/3}}{x ^{1/12}}$

Since $\frac{ x^{a} }{ x^{b} } = x ^{a-b}$
then $\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}$

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

$\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}$

Julie:
x times x to the second times x to the fifth = x * x² * x⁵

The thirty second root of the quantity of x times x to the second times x to the fifth is
 $\sqrt[32]{x* x^{2} * x^{5} }$

Since $x^{a}* x^{b}= x^{a+b}$
Then $\sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }$

Since $\sqrt[n]{x^{m}} = x^{m/n} }$
Then $\sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}$

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.

3 0

3 years ago